Propositional calculus

Not to be confused with Propositional analysis.

Propositional calculus is a branch of logic. It is also called propositional logic, statement logic, sentential calculus, sentential logic, or sometimes zeroth-order logic. It deals with propositions (which can be true or false) and relations between propositions, including the construction of arguments based on them. Compound propositions are formed by connecting propositions by logical connectives. Propositions that contain no logical connectives are called atomic propositions.

Unlike first-order logic, propositional logic does not deal with non-logical objects, predicates about them, or quantifiers. However, all the machinery of propositional logic is included in first-order logic and higher-order logics. In this sense, propositional logic is the foundation of first-order logic and higher-order logic.

Explanation

Logical connectives are found in natural languages. In English, some examples are "and" (conjunction), "or" (disjunction), "not" (negation) and "if" (but only when used to denote material conditional).

The following is an example of a very simple inference within the scope of propositional logic:

Premise 1: If it's raining then it's cloudy.

Premise 2: It's raining.

Conclusion: It's cloudy.

Both premises and the conclusion are propositions. The premises are taken for granted, and with the application of modus ponens (an inference rule), the conclusion follows.

As propositional logic is not concerned with the structure of propositions beyond the point where they cannot be decomposed any more by logical connectives, this inference can be restated replacing those atomic statements with statement letters, which are interpreted as variables representing statements:

Premise 1: ${\displaystyle P\to Q}$ 

Premise 2: ${\displaystyle P}$ 

Conclusion: ${\displaystyle Q}$ 

The same can be stated succinctly in the following way:

${\displaystyle {\frac {P\to Q,P}{Q}}}$ 

When P is interpreted as "It's raining" and Q as "it's cloudy" the above symbolic expressions can be seen to correspond exactly with the original expression in natural language. Not only that, but they will also correspond with any other inference of this form, which will be valid on the same basis this inference is.

Propositional logic may be studied through a formal system in which formulas of a formal language may be interpreted to represent propositions. A system of axioms and inference rules allows certain formulas to be derived. These derived formulas are called theorems and may be interpreted to be true propositions. A constructed sequence of such formulas is known as a derivation or proof and the last formula of the sequence is the theorem. The derivation may be interpreted as proof of the proposition represented by the theorem.

When a formal system is used to represent formal logic, only statement letters (usually capital roman letters such as ${\displaystyle P}$ , ${\displaystyle Q}$  and ${\displaystyle R}$ ) are represented directly. The natural language propositions that arise when they're interpreted are outside the scope of the system, and the relation between the formal system and its interpretation is likewise outside the formal system itself.

In classical truth-functional propositional logic, formulas are interpreted as having precisely one of two possible truth values, the truth value of true or the truth value of false.^[1] The principle of bivalence and the law of excluded middle are upheld. Truth-functional propositional logic defined as such and systems isomorphic to it are considered to be zeroth-order logic. However, alternative propositional logics are also possible. For more, see Other logical calculi below.

History

Main article: History of logic

Although propositional logic (which is interchangeable with propositional calculus) had been hinted by earlier philosophers, it was developed into a formal logic (Stoic logic) by Chrysippus in the 3rd century BC^[2] and expanded by his successor Stoics. The logic was focused on propositions. This advancement was different from the traditional syllogistic logic, which was focused on terms. However, most of the original writings were lost^[3] and the propositional logic developed by the Stoics was no longer understood later in antiquity.^{[citation needed]} Consequently, the system was essentially reinvented by Peter Abelard in the 12th century.^[4]

Propositional logic was eventually refined using symbolic logic. The 17th/18th-century mathematician Gottfried Leibniz has been credited with being the founder of symbolic logic for his work with the calculus ratiocinator. Although his work was the first of its kind, it was unknown to the larger logical community. Consequently, many of the advances achieved by Leibniz were recreated by logicians like George Boole and Augustus De Morgan—completely independent of Leibniz.^[5]

Just as propositional logic can be considered an advancement from the earlier syllogistic logic, Gottlob Frege's predicate logic can be also considered an advancement from the earlier propositional logic. One author describes predicate logic as combining "the distinctive features of syllogistic logic and propositional logic."^[6] Consequently, predicate logic ushered in a new era in logic's history; however, advances in propositional logic were still made after Frege, including natural deduction, truth trees and truth tables. Natural deduction was invented by Gerhard Gentzen and Stanisław Jaśkowski. Truth trees were invented by Evert Willem Beth.^[7] The invention of truth tables, however, is of uncertain attribution.

Within works by Frege^[8] and Bertrand Russell,^[9] are ideas influential to the invention of truth tables. The actual tabular structure (being formatted as a table), itself, is generally credited to either Ludwig Wittgenstein or Emil Post (or both, independently).^[8] Besides Frege and Russell, others credited with having ideas preceding truth tables include Philo, Boole, Charles Sanders Peirce,^[10] and Ernst Schröder. Others credited with the tabular structure include Jan Łukasiewicz, Alfred North Whitehead, William Stanley Jevons, John Venn, and Clarence Irving Lewis.^[9] Ultimately, some have concluded, like John Shosky, that "It is far from clear that any one person should be given the title of 'inventor' of truth-tables.".^[9]

Terminology

In general terms, a calculus is a formal system that consists of a set of syntactic expressions (well-formed formulas), a distinguished subset of these expressions (axioms), plus a set of formal rules that define a specific binary relation, intended to be interpreted as logical equivalence, on the space of expressions.

When the formal system is intended to be a logical system, the expressions are meant to be interpreted as statements, and the rules, known to be inference rules, are typically intended to be truth-preserving. In this setting, the rules, which may include axioms, can then be used to derive ("infer") formulas representing true statements—from given formulas representing true statements.

The set of axioms may be empty, a nonempty finite set, or a countably infinite set (see axiom schema). A formal grammar recursively defines the expressions and well-formed formulas of the language. In addition a semantics may be given which defines truth and valuations (or interpretations).

The language of a propositional calculus consists of

1. a set of primitive symbols, variously referred to as atomic formulas, placeholders, proposition letters, or variables, and
2. a set of operator symbols, variously interpreted as logical operators or logical connectives.

A well-formed formula is any atomic formula, or any formula that can be built up from atomic formulas by means of operator symbols according to the rules of the grammar.

Mathematicians sometimes distinguish between propositional constants, propositional variables, and schemata. Propositional constants represent some particular proposition, while propositional variables range over the set of all atomic propositions. Schemata, however, range over all propositions. It is common to represent propositional constants by A, B, and C, propositional variables by P, Q, and R, and schematic letters are often Greek letters, most often φ, ψ, and χ.

Basic concepts

The following outlines a standard propositional calculus. Many different formulations exist which are all more or less equivalent, but differ in the details of:

1. their language (i.e., the particular collection of primitive symbols and operator symbols),
2. the set of axioms, or distinguished formulas, and
3. the set of inference rules.

Any given proposition may be represented with a letter called a 'propositional constant', analogous to representing a number by a letter in mathematics (e.g., a = 5). All propositions require exactly one of two truth-values: true or false. For example, let P be the proposition that it is raining outside. This will be true (P) if it is raining outside, and false otherwise (¬P).

• We then define truth-functional operators, beginning with negation. ¬P represents the negation of P, which can be thought of as the denial of P. In the example above, ¬P expresses that it is not raining outside, or by a more standard reading: "It is not the case that it is raining outside." When P is true, ¬P is false; and when P is false, ¬P is true. As a result, ¬ ¬P always has the same truth-value as P.
• Conjunction is a truth-functional connective which forms a proposition out of two simpler propositions, for example, P and Q. The conjunction of P and Q is written P ∧ Q, and expresses that each are true. We read P ∧ Q as "P and Q". For any two propositions, there are four possible assignments of truth values:
  1. P is true and Q is true
  2. P is true and Q is false
  3. P is false and Q is true
  4. P is false and Q is false

The conjunction of P and Q is true in case 1, and is false otherwise. Where P is the proposition that it is raining outside and Q is the proposition that a cold-front is over Kansas, P ∧ Q is true when it is raining outside and there is a cold-front over Kansas. If it is not raining outside, then P ∧ Q is false; and if there is no cold-front over Kansas, then P ∧ Q is also false.

• Disjunction resembles conjunction in that it forms a proposition out of two simpler propositions. We write it P ∨ Q, and it is read "P or Q". It expresses that either P or Q is true. Thus, in the cases listed above, the disjunction of P with Q is true in all cases—except case 4. Using the example above, the disjunction expresses that it is either raining outside, or there is a cold front over Kansas. (Note, this use of disjunction is supposed to resemble the use of the English word "or". However, it is most like the English inclusive "or", which can be used to express the truth of at least one of two propositions. It is not like the English exclusive "or", which expresses the truth of exactly one of two propositions. In other words, the exclusive "or" is false when both P and Q are true (case 1), and similarly is false when both P and Q are false (case 4). An example of the exclusive or is: You may keep a cake (for later) or you may eat it all now, but you cannot both eat it all now and keep it for later. Often in natural language, given the appropriate context, the addendum "but not both" is omitted—but implied. In mathematics, however, "or" is always inclusive or; if exclusive or is meant it will be specified, possibly by "xor".)
• Material conditional also joins two simpler propositions, and we write P → Q, which is read "if P then Q". The proposition to the left of the arrow is called the antecedent, and the proposition to the right is called the consequent. (There is no such designation for conjunction or disjunction, since they are commutative operations.) It expresses that Q is true whenever P is true. Thus P → Q is true in every case above except case 2, because this is the only case when P is true but Q is not. Using the example, if P then Q expresses that if it is raining outside, then there is a cold-front over Kansas. The material conditional is often confused with physical causation. The material conditional, however, only relates two propositions by their truth-values—which is not the relation of cause and effect. It is contentious in the literature whether the material implication represents logical causation.
• Biconditional joins two simpler propositions, and we write P ↔ Q, which is read "P if and only if Q". It expresses that P and Q have the same truth-value, and in cases 1 and 4. 'P is true if and only if Q' is true, and is false otherwise.

It is very helpful to look at the truth tables for these different operators, as well as the method of analytic tableaux.

Closure under operations

Propositional logic is closed under truth-functional connectives. That is to say, for any proposition φ, ¬φ is also a proposition. Likewise, for any propositions φ and ψ, φ ∧ ψ is a proposition, and similarly for disjunction, conditional, and biconditional. This implies that, for instance, φ ∧ ψ is a proposition, and so it can be conjoined with another proposition. In order to represent this, we need to use parentheses to indicate which proposition is conjoined with which. For instance, P ∧ Q ∧ R is not a well-formed formula, because we do not know if we are conjoining P ∧ Q with R or if we are conjoining P with Q ∧ R. Thus we must write either (P ∧ Q) ∧ R to represent the former, or P ∧ (Q ∧ R) to represent the latter. By evaluating the truth conditions, we see that both expressions have the same truth conditions (will be true in the same cases), and moreover that any proposition formed by arbitrary conjunctions will have the same truth conditions, regardless of the location of the parentheses. This means that conjunction is associative, however, one should not assume that parentheses never serve a purpose. For instance, the sentence P ∧ (Q ∨ R) does not have the same truth conditions of (P ∧ Q) ∨ R, so they are different sentences distinguished only by the parentheses. One can verify this by the truth-table method referenced above.

Note: For any arbitrary number of propositional constants, we can form a finite number of cases which list their possible truth-values. A simple way to generate this is by truth-tables, in which one writes P, Q, ..., Z, for any list of k propositional constants—that is to say, any list of propositional constants with k entries. Below this list, one writes 2^k rows, and below P one fills in the first half of the rows with true (or T) and the second half with false (or F). Below Q one fills in one-quarter of the rows with T, then one-quarter with F, then one-quarter with T and the last quarter with F. The next column alternates between true and false for each eighth of the rows, then sixteenths, and so on, until the last propositional constant varies between T and F for each row. This will give a complete listing of cases or truth-value assignments possible for those propositional constants.

Argument

The propositional calculus then defines an argument to be a list of propositions. A valid argument is a list of propositions, the last of which follows from—or is implied by—the rest. All other arguments are invalid. The simplest valid argument is modus ponens, one instance of which is the following list of propositions:

${\displaystyle {\begin{array}{rl}1.&P\to Q\\2.&P\\\hline \therefore &Q\end{array}}}$ 

This is a list of three propositions, each line is a proposition, and the last follows from the rest. The first two lines are called premises, and the last line the conclusion. We say that any proposition C follows from any set of propositions ${\displaystyle (P_{1},...,P_{n})}$ , if C must be true whenever every member of the set ${\displaystyle (P_{1},...,P_{n})}$  is true. In the argument above, for any P and Q, whenever P → Q and P are true, necessarily Q is true. Notice that, when P is true, we cannot consider cases 3 and 4 (from the truth table). When P → Q is true, we cannot consider case 2. This leaves only case 1, in which Q is also true. Thus Q is implied by the premises.

This generalizes schematically. Thus, where φ and ψ may be any propositions at all,

${\displaystyle {\begin{array}{rl}1.&\varphi \to \psi \\2.&\varphi \\\hline \therefore &\psi \end{array}}}$ 

Other argument forms are convenient, but not necessary. Given a complete set of axioms (see below for one such set), modus ponens is sufficient to prove all other argument forms in propositional logic, thus they may be considered to be a derivative. Note, this is not true of the extension of propositional logic to other logics like first-order logic. First-order logic requires at least one additional rule of inference in order to obtain completeness.

The significance of argument in formal logic is that one may obtain new truths from established truths. In the first example above, given the two premises, the truth of Q is not yet known or stated. After the argument is made, Q is deduced. In this way, we define a deduction system to be a set of all propositions that may be deduced from another set of propositions. For instance, given the set of propositions ${\displaystyle A=\{P\lor Q,\neg Q\land R,(P\lor Q)\to R\}}$ , we can define a deduction system, Γ, which is the set of all propositions which follow from A. Reiteration is always assumed, so ${\displaystyle P\lor Q,\neg Q\land R,(P\lor Q)\to R\in \Gamma }$ . Also, from the first element of A, last element, as well as modus ponens, R is a consequence, and so ${\displaystyle R\in \Gamma }$ . Because we have not included sufficiently complete axioms, though, nothing else may be deduced. Thus, even though most deduction systems studied in propositional logic are able to deduce ${\displaystyle (P\lor Q)\leftrightarrow (\neg P\to Q)}$ , this one is too weak to prove such a proposition.

Generic description of a propositional calculus

A propositional calculus is a formal system ${\displaystyle {\mathcal {L}}={\mathcal {L}}\left(\mathrm {A} ,\ \Omega ,\ \mathrm {Z} ,\ \mathrm {I} \right)}$ , where:^{[citation needed]}

• The alpha set ${\displaystyle \mathrm {A} }$  is a countably infinite set of elements called proposition symbols or propositional variables. Syntactically speaking, these are the most basic elements of the formal language ${\displaystyle {\mathcal {L}}}$ , otherwise referred to as atomic formulas or terminal elements. In the examples to follow, the elements of ${\displaystyle \mathrm {A} }$  are typically the letters p, q, r, and so on.
• The omega set Ω is a finite set of elements called operator symbols or logical connectives. The set Ω is partitioned into disjoint subsets as follows:

  ${\displaystyle \Omega =\Omega _{0}\cup \Omega _{1}\cup \cdots \cup \Omega _{j}\cup \cdots \cup \Omega _{m}.}$ 

  In this partition, ${\displaystyle \Omega _{j}}$  is the set of operator symbols of arity j.

  In the more familiar propositional calculi, Ω is typically partitioned as follows:

  ${\displaystyle \Omega _{1}=\{\lnot \},}$ 

  ${\displaystyle \Omega _{2}\subseteq \{\land ,\lor ,\to ,\leftrightarrow \}.}$ 

  A frequently adopted convention treats the constant logical values as operators of arity zero, thus:

  ${\displaystyle \Omega _{0}=\{\bot ,\top \}.}$ 

  Some writers use the tilde (~), or N, instead of ¬; and some use v instead of ${\displaystyle \vee }$  as well as the ampersand (&), the prefixed K, or ${\displaystyle \cdot }$  instead of ${\displaystyle \wedge }$ . Notation varies even more for the set of logical values, with symbols like {false, true}, {F, T}, or {0, 1} all being seen in various contexts instead of ${\displaystyle \{\bot ,\top \}}$ .
• The zeta set ${\displaystyle \mathrm {Z} }$  is a finite set of transformation rules that are called inference rules when they acquire logical applications.
• The iota set ${\displaystyle \mathrm {I} }$  is a countable set of initial points that are called axioms when they receive logical interpretations.

The language of ${\displaystyle {\mathcal {L}}}$ , also known as its set of formulas, well-formed formulas, is inductively defined by the following rules:

1. Base: Any element of the alpha set ${\displaystyle \mathrm {A} }$  is a formula of ${\displaystyle {\mathcal {L}}}$ .
2. If ${\displaystyle p_{1},p_{2},\ldots ,p_{j}}$  are formulas and ${\displaystyle f}$  is in ${\displaystyle \Omega _{j}}$ , then ${\displaystyle fp_{1}p_{2}\ldots p_{j}}$  is a formula.
3. Closed: Nothing else is a formula of ${\displaystyle {\mathcal {L}}}$ .

Repeated applications of these rules permits the construction of complex formulas. For example:

• By rule 1, p is a formula.
• By rule 2, ${\displaystyle \neg p}$  is a formula.
• By rule 1, q is a formula.
• By rule 2, ${\displaystyle \neg p\lor q}$  is a formula.^{[note 1]}

Example 1. Simple axiom system

Let ${\displaystyle {\mathcal {L}}_{1}={\mathcal {L}}(\mathrm {A} ,\Omega ,\mathrm {Z} ,\mathrm {I} )}$ , where ${\displaystyle \mathrm {A} }$ , ${\displaystyle \Omega }$ , ${\displaystyle \mathrm {Z} }$ , ${\displaystyle \mathrm {I} }$  are defined as follows:

• The set ${\displaystyle \mathrm {A} }$ , the countably infinite set of symbols that serve to represent logical propositions:

  ${\displaystyle \mathrm {A} =\{p,q,r,s,t,u,p_{2},\ldots \}.}$ 

• The functionally complete set ${\displaystyle \Omega }$  of logical operators (logical connectives and negation) is as follows. Of the three connectives for conjunction, disjunction, and implication (${\displaystyle \wedge ,\lor }$ , and →), one can be taken as primitive and the other two can be defined in terms of it and negation (¬).^[11] Alternatively, all of the logical operators may be defined in terms of a sole sufficient operator, such as the Sheffer stroke (nand). The biconditional (${\displaystyle a\leftrightarrow b}$ ) can of course be defined in terms of conjunction and implication as ${\displaystyle (a\to b)\land (b\to a)}$ .
  Adopting negation and implication as the two primitive operations of a propositional calculus is tantamount to having the omega set ${\displaystyle \Omega =\Omega _{1}\cup \Omega _{2}}$  partition as follows:

  ${\displaystyle \Omega _{1}=\{\lnot \},}$ 

  ${\displaystyle \Omega _{2}=\{\to \}.}$ 

Then ${\displaystyle a\lor b}$  is defined as ${\displaystyle \neg a\to b}$ , and ${\displaystyle a\land b}$  is defined as ${\displaystyle \neg (a\to \neg b)}$ .

• The set ${\displaystyle \mathrm {I} }$  (the set of initial points of logical deduction, i.e., logical axioms) is the axiom system proposed by Jan Łukasiewicz, and used as the propositional-calculus part of a Hilbert system. The axioms are all substitution instances of:
  • ${\displaystyle p\to (q\to p)}$ 
  • ${\displaystyle (p\to (q\to r))\to ((p\to q)\to (p\to r))}$ 
  • ${\displaystyle (\neg p\to \neg q)\to (q\to p)}$ 
• The set ${\displaystyle \mathrm {Z} }$  of transformation rules (rules of inference) is the sole rule modus ponens (i.e., from any formulas of the form ${\displaystyle \varphi }$  and ${\displaystyle (\varphi \to \psi )}$ , infer ${\displaystyle \psi }$ ).

This system is used in Metamath set.mm formal proof database.

Example 2. Natural deduction system

Let ${\displaystyle {\mathcal {L}}_{2}={\mathcal {L}}(\mathrm {A} ,\Omega ,\mathrm {Z} ,\mathrm {I} )}$ , where ${\displaystyle \mathrm {A} }$ , ${\displaystyle \Omega }$ , ${\displaystyle \mathrm {Z} }$ , ${\displaystyle \mathrm {I} }$  are defined as follows:

• The alpha set ${\displaystyle \mathrm {A} }$ , is a countably infinite set of symbols, for example:

  ${\displaystyle \mathrm {A} =\{p,q,r,s,t,u,p_{2},\ldots \}.}$ 

• The omega set ${\displaystyle \Omega =\Omega _{1}\cup \Omega _{2}}$  partitions as follows:

  ${\displaystyle \Omega _{1}=\{\lnot \},}$ 

  ${\displaystyle \Omega _{2}=\{\land ,\lor ,\to ,\leftrightarrow \}.}$ 

In the following example of a propositional calculus, the transformation rules are intended to be interpreted as the inference rules of a so-called natural deduction system. The particular system presented here has no initial points, which means that its interpretation for logical applications derives its theorems from an empty axiom set.

• The set of initial points is empty, that is, ${\displaystyle \mathrm {I} =\varnothing }$ .
• The set of transformation rules, ${\displaystyle \mathrm {Z} }$ , is described as follows:

Our propositional calculus has eleven inference rules. These rules allow us to derive other true formulas given a set of formulas that are assumed to be true. The first ten simply state that we can infer certain well-formed formulas from other well-formed formulas. The last rule however uses hypothetical reasoning in the sense that in the premise of the rule we temporarily assume an (unproven) hypothesis to be part of the set of inferred formulas to see if we can infer a certain other formula. Since the first ten rules do not do this they are usually described as non-hypothetical rules, and the last one as a hypothetical rule.

In describing the transformation rules, we may introduce a metalanguage symbol ${\displaystyle \vdash }$ . It is basically a convenient shorthand for saying "infer that". The format is ${\displaystyle \Gamma \vdash \psi }$ , in which Γ is a (possibly empty) set of formulas called premises, and ψ is a formula called conclusion. The transformation rule ${\displaystyle \Gamma \vdash \psi }$  means that if every proposition in Γ is a theorem (or has the same truth value as the axioms), then ψ is also a theorem. Considering the following rule Conjunction introduction, we will know whenever Γ has more than one formula, we can always safely reduce it into one formula using conjunction. So for short, from that time on we may represent Γ as one formula instead of a set. Another omission for convenience is when Γ is an empty set, in which case Γ may not appear.

Negation introduction

From ${\displaystyle (p\to q)}$  and ${\displaystyle (p\to \neg q)}$ , infer ${\displaystyle \neg p}$ .

That is, ${\displaystyle \{(p\to q),(p\to \neg q)\}\vdash \neg p}$ .

Negation elimination

From ${\displaystyle \neg p}$ , infer ${\displaystyle (p\to r)}$ .

That is, ${\displaystyle \{\neg p\}\vdash (p\to r)}$ .

Double negation elimination

From ${\displaystyle \neg \neg p}$ , infer p.

That is, ${\displaystyle \neg \neg p\vdash p}$ .

Conjunction introduction

From p and q, infer ${\displaystyle (p\land q)}$ .

That is, ${\displaystyle \{p,q\}\vdash (p\land q)}$ .

Conjunction elimination

From ${\displaystyle (p\land q)}$ , infer p.

From ${\displaystyle (p\land q)}$ , infer q.

That is, ${\displaystyle (p\land q)\vdash p}$  and ${\displaystyle (p\land q)\vdash q}$ .

Disjunction introduction

From p, infer ${\displaystyle (p\lor q)}$ .

From q, infer ${\displaystyle (p\lor q)}$ .

That is, ${\displaystyle p\vdash (p\lor q)}$  and ${\displaystyle q\vdash (p\lor q)}$ .

Disjunction elimination

From ${\displaystyle (p\lor q)}$  and ${\displaystyle (p\to r)}$  and ${\displaystyle (q\to r)}$ , infer r.

That is, ${\displaystyle \{p\lor q,p\to r,q\to r\}\vdash r}$ .

Biconditional introduction

From ${\displaystyle (p\to q)}$  and ${\displaystyle (q\to p)}$ , infer ${\displaystyle (p\leftrightarrow q)}$ .

That is, ${\displaystyle \{p\to q,q\to p\}\vdash (p\leftrightarrow q)}$ .

Biconditional elimination

From ${\displaystyle (p\leftrightarrow q)}$ , infer ${\displaystyle (p\to q)}$ .

From ${\displaystyle (p\leftrightarrow q)}$ , infer ${\displaystyle (q\to p)}$ .

That is, ${\displaystyle (p\leftrightarrow q)\vdash (p\to q)}$  and ${\displaystyle (p\leftrightarrow q)\vdash (q\to p)}$ .

Modus ponens (conditional elimination)

From p and ${\displaystyle (p\to q)}$ , infer q.

That is, ${\displaystyle \{p,p\to q\}\vdash q}$ .

Conditional proof (conditional introduction)

From [accepting p allows a proof of q], infer ${\displaystyle (p\to q)}$ .

That is, ${\displaystyle (p\vdash q)\vdash (p\to q)}$ .

Basic and derived argument forms

Name	Sequent^[12]	Description
Modus Ponens	${\displaystyle ((p\to q)\land p)\vdash q}$	If p then q; p; therefore q
Modus Tollens	${\displaystyle ((p\to q)\land \neg q)\vdash \neg p}$	If p then q; not q; therefore not p
Hypothetical Syllogism	${\displaystyle ((p\to q)\land (q\to r))\vdash (p\to r)}$	If p then q; if q then r; therefore, if p then r
Disjunctive Syllogism	${\displaystyle ((p\lor q)\land \neg p)\vdash q}$	Either p or q, or both; not p; therefore, q
Constructive Dilemma	${\displaystyle ((p\to q)\land (r\to s)\land (p\lor r))\vdash (q\lor s)}$	If p then q; and if r then s; but p or r; therefore q or s
Destructive Dilemma	${\displaystyle ((p\to q)\land (r\to s)\land (\neg q\lor \neg s))\vdash (\neg p\lor \neg r)}$	If p then q; and if r then s; but not q or not s; therefore not p or not r
Bidirectional Dilemma	${\displaystyle ((p\to q)\land (r\to s)\land (p\lor \neg s))\vdash (q\lor \neg r)}$	If p then q; and if r then s; but p or not s; therefore q or not r
Simplification	${\displaystyle (p\land q)\vdash p}$	p and q are true; therefore p is true
Conjunction	${\displaystyle p,q\vdash (p\land q)}$	p and q are true separately; therefore they are true conjointly
Addition	${\displaystyle p\vdash (p\lor q)}$	p is true; therefore the disjunction (p or q) is true
Composition	${\displaystyle ((p\to q)\land (p\to r))\vdash (p\to (q\land r))}$	If p then q; and if p then r; therefore if p is true then q and r are true
De Morgan's Theorem (1)	${\displaystyle \neg (p\land q)\dashv \vdash (\neg p\lor \neg q)}$	The negation of (p and q) is equiv. to (not p or not q)
De Morgan's Theorem (2)	${\displaystyle \neg (p\lor q)\dashv \vdash (\neg p\land \neg q)}$	The negation of (p or q) is equiv. to (not p and not q)
Commutation (1)	${\displaystyle (p\lor q)\dashv \vdash (q\lor p)}$	(p or q) is equiv. to (q or p)
Commutation (2)	${\displaystyle (p\land q)\dashv \vdash (q\land p)}$	(p and q) is equiv. to (q and p)
Commutation (3)	${\displaystyle (p\leftrightarrow q)\dashv \vdash (q\leftrightarrow p)}$	(p iff q) is equiv. to (q iff p)
Association (1)	${\displaystyle (p\lor (q\lor r))\dashv \vdash ((p\lor q)\lor r)}$	p or (q or r) is equiv. to (p or q) or r
Association (2)	${\displaystyle (p\land (q\land r))\dashv \vdash ((p\land q)\land r)}$	p and (q and r) is equiv. to (p and q) and r
Distribution (1)	${\displaystyle (p\land (q\lor r))\dashv \vdash ((p\land q)\lor (p\land r))}$	p and (q or r) is equiv. to (p and q) or (p and r)
Distribution (2)	${\displaystyle (p\lor (q\land r))\dashv \vdash ((p\lor q)\land (p\lor r))}$	p or (q and r) is equiv. to (p or q) and (p or r)
Double Negation	${\displaystyle p\dashv \vdash \neg \neg p}$	p is equivalent to the negation of not p
Transposition	${\displaystyle (p\to q)\dashv \vdash (\neg q\to \neg p)}$	If p then q is equiv. to if not q then not p
Material Implication	${\displaystyle (p\to q)\dashv \vdash (\neg p\lor q)}$	If p then q is equiv. to not p or q
Material Equivalence (1)	${\displaystyle (p\leftrightarrow q)\dashv \vdash ((p\to q)\land (q\to p))}$	(p iff q) is equiv. to (if p is true then q is true) and (if q is true then p is true)
Material Equivalence (2)	${\displaystyle (p\leftrightarrow q)\dashv \vdash ((p\land q)\lor (\neg p\land \neg q))}$	(p iff q) is equiv. to either (p and q are true) or (both p and q are false)
Material Equivalence (3)	${\displaystyle (p\leftrightarrow q)\dashv \vdash ((p\lor \neg q)\land (\neg p\lor q))}$	(p iff q) is equiv to., both (p or not q is true) and (not p or q is true)
Exportation^[13]	${\displaystyle ((p\land q)\to r)\vdash (p\to (q\to r))}$	from (if p and q are true then r is true) we can prove (if q is true then r is true, if p is true)
Importation	${\displaystyle (p\to (q\to r))\dashv \vdash ((p\land q)\to r)}$	If p then (if q then r) is equivalent to if p and q then r
Tautology (1)	${\displaystyle p\dashv \vdash (p\lor p)}$	p is true is equiv. to p is true or p is true
Tautology (2)	${\displaystyle p\dashv \vdash (p\land p)}$	p is true is equiv. to p is true and p is true
Tertium non datur (Law of Excluded Middle)	${\displaystyle \vdash (p\lor \neg p)}$	p or not p is true
Law of Non-Contradiction	${\displaystyle \vdash \neg (p\land \neg p)}$	p and not p is false, is a true statement

Proofs in propositional calculus

One of the main uses of a propositional calculus, when interpreted for logical applications, is to determine relations of logical equivalence between propositional formulas. These relationships are determined by means of the available transformation rules, sequences of which are called derivations or proofs.

In the discussion to follow, a proof is presented as a sequence of numbered lines, with each line consisting of a single formula followed by a reason or justification for introducing that formula. Each premise of the argument, that is, an assumption introduced as an hypothesis of the argument, is listed at the beginning of the sequence and is marked as a "premise" in lieu of other justification. The conclusion is listed on the last line. A proof is complete if every line follows from the previous ones by the correct application of a transformation rule. (For a contrasting approach, see proof-trees).

Example of a proof in natural deduction system

• To be shown that A → A.
• One possible proof of this (which, though valid, happens to contain more steps than are necessary) may be arranged as follows:

Example of a proof

Number	Formula	Reason
1	${\displaystyle A}$	premise
2	${\displaystyle A\lor A}$	From (1) by disjunction introduction
3	${\displaystyle (A\lor A)\land A}$	From (1) and (2) by conjunction introduction
4	${\displaystyle A}$	From (3) by conjunction elimination
5	${\displaystyle A\vdash A}$	Summary of (1) through (4)
6	${\displaystyle \vdash A\to A}$	From (5) by conditional proof

Interpret ${\displaystyle A\vdash A}$  as "Assuming A, infer A". Read ${\displaystyle \vdash A\to A}$  as "Assuming nothing, infer that A implies A", or "It is a tautology that A implies A", or "It is always true that A implies A".

Example of a proof in a classical propositional calculus system

We now prove the same theorem ${\displaystyle A\to A}$  in the axiomatic system by Jan Łukasiewicz described above, which is an example of a Hilbert-style deductive system for the classical propositional calculus.

The axioms are:

(A1) ${\displaystyle (p\to (q\to p))}$ 

(A2) ${\displaystyle ((p\to (q\to r))\to ((p\to q)\to (p\to r)))}$ 

(A3) ${\displaystyle ((\neg p\to \neg q)\to (q\to p))}$ 

And the proof is as follows:

1. ${\displaystyle A\to ((B\to A)\to A)}$        (instance of (A1))
2. ${\displaystyle (A\to ((B\to A)\to A))\to ((A\to (B\to A))\to (A\to A))}$        (instance of (A2))
3. ${\displaystyle (A\to (B\to A))\to (A\to A)}$        (from (1) and (2) by modus ponens)
4. ${\displaystyle A\to (B\to A)}$        (instance of (A1))
5. ${\displaystyle A\to A}$        (from (4) and (3) by modus ponens)

Soundness and completeness of the rules

The crucial properties of this set of rules are that they are sound and complete. Informally this means that the rules are correct and that no other rules are required. These claims can be made more formal as follows. The proofs for the soundness and completeness of the propositional logic are not themselves proofs in propositional logic ; these are theorems in ZFC used as a metatheory to prove properties of propositional logic.

We define a truth assignment as a function that maps propositional variables to true or false. Informally such a truth assignment can be understood as the description of a possible state of affairs (or possible world) where certain statements are true and others are not. The semantics of formulas can then be formalized by defining for which "state of affairs" they are considered to be true, which is what is done by the following definition.

We define when such a truth assignment A satisfies a certain well-formed formula with the following rules:

• A satisfies the propositional variable P if and only if A(P) = true
• A satisfies ¬φ if and only if A does not satisfy φ
• A satisfies (φ ∧ ψ) if and only if A satisfies both φ and ψ
• A satisfies (φ ∨ ψ) if and only if A satisfies at least one of either φ or ψ
• A satisfies (φ → ψ) if and only if it is not the case that A satisfies φ but not ψ
• A satisfies (φ ↔ ψ) if and only if A satisfies both φ and ψ or satisfies neither one of them

With this definition we can now formalize what it means for a formula φ to be implied by a certain set S of formulas. Informally this is true if in all worlds that are possible given the set of formulas S the formula φ also holds. This leads to the following formal definition: We say that a set S of well-formed formulas semantically entails (or implies) a certain well-formed formula φ if all truth assignments that satisfy all the formulas in S also satisfy φ.

Finally we define syntactical entailment such that φ is syntactically entailed by S if and only if we can derive it with the inference rules that were presented above in a finite number of steps. This allows us to formulate exactly what it means for the set of inference rules to be sound and complete:

Soundness: If the set of well-formed formulas S syntactically entails the well-formed formula φ then S semantically entails φ.

Completeness: If the set of well-formed formulas S semantically entails the well-formed formula φ then S syntactically entails φ.

For the above set of rules this is indeed the case.

Sketch of a soundness proof

(For most logical systems, this is the comparatively "simple" direction of proof)

Notational conventions: Let G be a variable ranging over sets of sentences. Let A, B and C range over sentences. For "G syntactically entails A" we write "G proves A". For "G semantically entails A" we write "G implies A".

We want to show: (A)(G) (if G proves A, then G implies A).

We note that "G proves A" has an inductive definition, and that gives us the immediate resources for demonstrating claims of the form "If G proves A, then ...". So our proof proceeds by induction.

1. Basis. Show: If A is a member of G, then G implies A.
2. Basis. Show: If A is an axiom, then G implies A.
3. Inductive step (induction on n, the length of the proof):
   1. Assume for arbitrary G and A that if G proves A in n or fewer steps, then G implies A.
   2. For each possible application of a rule of inference at step n + 1, leading to a new theorem B, show that G implies B.

Notice that Basis Step II can be omitted for natural deduction systems because they have no axioms. When used, Step II involves showing that each of the axioms is a (semantic) logical truth.

The Basis steps demonstrate that the simplest provable sentences from G are also implied by G, for any G. (The proof is simple, since the semantic fact that a set implies any of its members, is also trivial.) The Inductive step will systematically cover all the further sentences that might be provable—by considering each case where we might reach a logical conclusion using an inference rule—and shows that if a new sentence is provable, it is also logically implied. (For example, we might have a rule telling us that from "A" we can derive "A or B". In III.a We assume that if A is provable it is implied. We also know that if A is provable then "A or B" is provable. We have to show that then "A or B" too is implied. We do so by appeal to the semantic definition and the assumption we just made. A is provable from G, we assume. So it is also implied by G. So any semantic valuation making all of G true makes A true. But any valuation making A true makes "A or B" true, by the defined semantics for "or". So any valuation which makes all of G true makes "A or B" true. So "A or B" is implied.) Generally, the Inductive step will consist of a lengthy but simple case-by-case analysis of all the rules of inference, showing that each "preserves" semantic implication.

By the definition of provability, there are no sentences provable other than by being a member of G, an axiom, or following by a rule; so if all of those are semantically implied, the deduction calculus is sound.

Sketch of completeness proof

(This is usually the much harder direction of proof.)

We adopt the same notational conventions as above.

We want to show: If G implies A, then G proves A. We proceed by contraposition: We show instead that if G does not prove A then G does not imply A. If we show that there is a model where A does not hold despite G being true, then obviously G does not imply A. The idea is to build such a model out of our very assumption that G does not prove A.

1. G does not prove A. (Assumption)
2. If G does not prove A, then we can construct an (infinite) Maximal Set, G^∗, which is a superset of G and which also does not prove A.
   1. Place an ordering (with order type ω) on all the sentences in the language (e.g., shortest first, and equally long ones in extended alphabetical ordering), and number them (E₁, E₂, ...)
   2. Define a series G_n of sets (G₀, G₁, ...) inductively:
      1. ${\displaystyle G_{0}=G}$ 
      2. If ${\displaystyle G_{k}\cup \{E_{k+1}\}}$  proves A, then ${\displaystyle G_{k+1}=G_{k}}$ 
      3. If ${\displaystyle G_{k}\cup \{E_{k+1}\}}$  does not prove A, then ${\displaystyle G_{k+1}=G_{k}\cup \{E_{k+1}\}}$ 
   3. Define G^∗ as the union of all the G_n. (That is, G^∗ is the set of all the sentences that are in any G_n.)
   4. It can be easily shown that
      1. G^∗ contains (is a superset of) G (by (b.i));
      2. G^∗ does not prove A (because the proof would contain only finitely many sentences and when the last of them is introduced in some G_n, that G_n would prove A contrary to the definition of G_n); and
      3. G^∗ is a Maximal Set with respect to A: If any more sentences whatever were added to G^∗, it would prove A. (Because if it were possible to add any more sentences, they should have been added when they were encountered during the construction of the G_n, again by definition)
3. If G^∗ is a Maximal Set with respect to A, then it is truth-like. This means that it contains C if and only if it does not contain ¬C; If it contains C and contains "If C then B" then it also contains B; and so forth. In order to show this, one has to show the axiomatic system is strong enough for the following:
   • For any formulas C and D, if it proves both C and ¬C, then it proves D. From this it follows, that a Maximal Set with respect to A cannot prove both C and ¬C, as otherwise it would prove A.
   • For any formulas C and D, if it proves both C→D and ¬C→D, then it proves D. This is used, together with the deduction theorem, to show that for any formula, either it or its negation is in G^∗: Let B be a formula not in G^∗; then G^∗ with the addition of B proves A. Thus from the deduction theorem it follows that G^∗ proves B→A. But suppose ¬B were also not in G^∗, then by the same logic G^∗ also proves ¬B→A; but then G^∗ proves A, which we have already shown to be false.
   • For any formulas C and D, if it proves C and D, then it proves C→D.
   • For any formulas C and D, if it proves C and ¬D, then it proves ¬(C→D).
   • For any formulas C and D, if it proves ¬C, then it proves C→D.
   If additional logical operation (such as conjunction and/or disjunction) are part of the vocabulary as well, then there are additional requirement on the axiomatic system (e.g. that if it proves C and D, it would also prove their conjunction).
4. If G^∗ is truth-like there is a G^∗-Canonical valuation of the language: one that makes every sentence in G^∗ true and everything outside G^∗ false while still obeying the laws of semantic composition in the language. The requirement that it is truth-like is needed to guarantee that the laws of semantic composition in the language will be satisfied by this truth assignment.
5. A G^∗-canonical valuation will make our original set G all true, and make A false.
6. If there is a valuation on which G are true and A is false, then G does not (semantically) imply A.

Thus every system that has modus ponens as an inference rule, and proves the following theorems (including substitutions thereof) is complete:

• ${\displaystyle p\to (\neg p\to q)}$ 
• ${\displaystyle (p\to q)\to ((\neg p\to q)\to q)}$ 
• ${\displaystyle p\to (q\to (p\to q))}$ 
• ${\displaystyle p\to (\neg q\to \neg (p\to q))}$ 
• ${\displaystyle \neg p\to (p\to q)}$ 
• ${\displaystyle p\to p}$ 
• ${\displaystyle p\to (q\to p)}$ 
• ${\displaystyle (p\to (q\to r))\to ((p\to q)\to (p\to r))}$ 

The first five are used for the satisfaction of the five conditions in stage III above, and the last three for proving the deduction theorem.

Example

As an example, it can be shown that as any other tautology, the three axioms of the classical propositional calculus system described earlier can be proven in any system that satisfies the above, namely that has modus ponens as an inference rule, and proves the above eight theorems (including substitutions thereof). Out of the eight theorems, the last two are two of the three axioms; the third axiom, ${\displaystyle (\neg q\to \neg p)\to (p\to q)}$ , can be proven as well, as we now show.

For the proof we may use the hypothetical syllogism theorem (in the form relevant for this axiomatic system), since it only relies on the two axioms that are already in the above set of eight theorems. The proof then is as follows:

1. ${\displaystyle q\to (p\to q)}$        (instance of the 7th theorem)
2. ${\displaystyle (q\to (p\to q))\to ((\neg q\to \neg p)\to (q\to (p\to q)))}$        (instance of the 7th theorem)
3. ${\displaystyle (\neg q\to \neg p)\to (q\to (p\to q))}$        (from (1) and (2) by modus ponens)
4. ${\displaystyle (\neg p\to (p\to q))\to ((\neg q\to \neg p)\to (\neg q\to (p\to q)))}$        (instance of the hypothetical syllogism theorem)
5. ${\displaystyle (\neg p\to (p\to q))}$        (instance of the 5th theorem)
6. ${\displaystyle (\neg q\to \neg p)\to (\neg q\to (p\to q))}$        (from (5) and (4) by modus ponens)
7. ${\displaystyle (q\to (p\to q))\to ((\neg q\to (p\to q))\to (p\to q))}$        (instance of the 2nd theorem)
8. ${\displaystyle ((q\to (p\to q))\to ((\neg q\to (p\to q))\to (p\to q)))\to ((\neg q\to \neg p)\to ((q\to (p\to q))\to ((\neg q\to (p\to q))\to (p\to q))))}$        (instance of the 7th theorem)
9. ${\displaystyle (\neg q\to \neg p)\to ((q\to (p\to q))\to ((\neg q\to (p\to q))\to (p\to q)))}$        (from (7) and (8) by modus ponens)
10. ${\displaystyle ((\neg q\to \neg p)\to ((q\to (p\to q))\to ((\neg q\to (p\to q))\to (p\to q))))\to }$ 

    ${\displaystyle (((\neg q\to \neg p)\to (q\to (p\to q)))\to ((\neg q\to \neg p)\to ((\neg q\to (p\to q))\to (p\to q))))}$        (instance of the 8th theorem)

11. ${\displaystyle ((\neg q\to \neg p)\to (q\to (p\to q)))\to ((\neg q\to \neg p)\to ((\neg q\to (p\to q))\to (p\to q)))}$        (from (9) and (10) by modus ponens)
12. ${\displaystyle (\neg q\to \neg p)\to ((\neg q\to (p\to q))\to (p\to q))}$        (from (3) and (11) by modus ponens)
13. ${\displaystyle ((\neg q\to \neg p)\to ((\neg q\to (p\to q))\to (p\to q)))\to (((\neg q\to \neg p)\to (\neg q\to (p\to q)))\to ((\neg q\to \neg p)\to (p\to q)))}$        (instance of the 8th theorem)
14. ${\displaystyle ((\neg q\to \neg p)\to (\neg q\to (p\to q)))\to ((\neg q\to \neg p)\to (p\to q))}$        (from (12) and (13) by modus ponens)
15. ${\displaystyle (\neg q\to \neg p)\to (p\to q)}$        (from (6) and (14) by modus ponens)

Verifying completeness for the classical propositional calculus system

We now verify that the classical propositional calculus system described earlier can indeed prove the required eight theorems mentioned above. We use several lemmas proven here:

(DN1) ${\displaystyle \neg \neg p\to p}$  - Double negation (one direction)

(DN2) ${\displaystyle p\to \neg \neg p}$  - Double negation (another direction)

(HS1) ${\displaystyle (q\to r)\to ((p\to q)\to (p\to r))}$  - one form of Hypothetical syllogism

(HS2) ${\displaystyle (p\to q)\to ((q\to r)\to (p\to r))}$  - another form of Hypothetical syllogism

(TR1) ${\displaystyle (p\to q)\to (\neg q\to \neg p)}$  - Transposition

(TR2) ${\displaystyle (\neg p\to q)\to (\neg q\to p)}$  - another form of transposition.

(L1) ${\displaystyle p\to ((p\to q)\to q)}$ 

(L3) ${\displaystyle (\neg p\to p)\to p}$ 

We also use the method of the hypothetical syllogism metatheorem as a shorthand for several proof steps.

• ${\displaystyle p\to (\neg p\to q)}$  - proof:
  1. ${\displaystyle p\to (\neg q\to p)}$        (instance of (A1))
  2. ${\displaystyle (\neg q\to p)\to (\neg p\to \neg \neg q)}$        (instance of (TR1))
  3. ${\displaystyle p\to (\neg p\to \neg \neg q)}$        (from (1) and (2) using the hypothetical syllogism metatheorem)
  4. ${\displaystyle \neg \neg q\to q}$        (instance of (DN1))
  5. ${\displaystyle (\neg \neg q\to q)\to ((\neg p\to \neg \neg q)\to (\neg p\to q))}$        (instance of (HS1))
  6. ${\displaystyle (\neg p\to \neg \neg q)\to (\neg p\to q)}$        (from (4) and (5) using modus ponens)
  7. ${\displaystyle p\to (\neg p\to q)}$        (from (3) and (6) using the hypothetical syllogism metatheorem)
• ${\displaystyle (p\to q)\to ((\neg p\to q)\to q)}$  - proof:
  1. ${\displaystyle (p\to q)\to ((\neg q\to p)\to (\neg q\to q))}$        (instance of (HS1))
  2. ${\displaystyle (\neg q\to q)\to q}$        (instance of (L3))
  3. ${\displaystyle ((\neg q\to q)\to q)\to (((\neg q\to p)\to (\neg q\to q))\to ((\neg q\to p)\to q))}$        (instance of (HS1))
  4. ${\displaystyle ((\neg q\to p)\to (\neg q\to q))\to ((\neg q\to p)\to q)}$        (from (2) and (3) by modus ponens)
  5. ${\displaystyle (p\to q)\to ((\neg q\to p)\to q)}$        (from (1) and (4) using the hypothetical syllogism metatheorem)
  6. ${\displaystyle (\neg p\to q)\to (\neg q\to p)}$        (instance of (TR2))
  7. ${\displaystyle ((\neg p\to q)\to (\neg q\to p))\to (((\neg q\to p)\to q)\to ((\neg p\to q)\to q))}$        (instance of (HS2))
  8. ${\displaystyle ((\neg q\to p)\to q)\to ((\neg p\to q)\to q)}$        (from (6) and (7) using modus ponens)
  9. ${\displaystyle (p\to q)\to ((\neg p\to q)\to q)}$        (from (5) and (8) using the hypothetical syllogism metatheorem)
• ${\displaystyle p\to (q\to (p\to q))}$  - proof:
  1. ${\displaystyle q\to (p\to q)}$        (instance of (A1))
  2. ${\displaystyle (q\to (p\to q))\to (p\to (q\to (p\to q)))}$        (instance of (A1))
  3. ${\displaystyle p\to (q\to (p\to q))}$        (from (1) and (2) using modus ponens)
• ${\displaystyle p\to (\neg q\to \neg (p\to q))}$  - proof:
  1. ${\displaystyle p\to ((p\to q)\to q)}$        (instance of (L1))
  2. ${\displaystyle ((p\to q)\to q)\to (\neg q\to \neg (p\to q))}$        (instance of (TR1))
  3. ${\displaystyle p\to (\neg q\to \neg (p\to q))}$        (from (1) and (2) using the hypothetical syllogism metatheorem)
• ${\displaystyle \neg p\to (p\to q)}$  - proof:
  1. ${\displaystyle \neg p\to (\neg q\to \neg p)}$        (instance of (A1))
  2. ${\displaystyle (\neg q\to \neg p)\to (p\to q)}$        (instance of (A3))
  3. ${\displaystyle \neg p\to (p\to q)}$        (from (1) and (2) using the hypothetical syllogism metatheorem)
• ${\displaystyle p\to p}$  - proof given in the proof example above
• ${\displaystyle p\to (q\to p)}$  - axiom (A1)
• ${\displaystyle (p\to (q\to r))\to ((p\to q)\to (p\to r))}$  - axiom (A2)

Another outline for a completeness proof

If a formula is a tautology, then there is a truth table for it which shows that each valuation yields the value true for the formula. Consider such a valuation. By mathematical induction on the length of the subformulas, show that the truth or falsity of the subformula follows from the truth or falsity (as appropriate for the valuation) of each propositional variable in the subformula. Then combine the lines of the truth table together two at a time by using "(P is true implies S) implies ((P is false implies S) implies S)". Keep repeating this until all dependencies on propositional variables have been eliminated. The result is that we have proved the given tautology. Since every tautology is provable, the logic is complete.

Interpretation of a truth-functional propositional calculus

An interpretation of a truth-functional propositional calculus ${\displaystyle {\mathcal {P}}}$  is an assignment to each propositional symbol of ${\displaystyle {\mathcal {P}}}$  of one or the other (but not both) of the truth values truth (T) and falsity (F), and an assignment to the connective symbols of ${\displaystyle {\mathcal {P}}}$  of their usual truth-functional meanings. An interpretation of a truth-functional propositional calculus may also be expressed in terms of truth tables.^[14]

For ${\displaystyle n}$  distinct propositional symbols there are ${\displaystyle 2^{n}}$  distinct possible interpretations. For any particular symbol ${\displaystyle a}$ , for example, there are ${\displaystyle 2^{1}=2}$  possible interpretations:

1. ${\displaystyle a}$  is assigned T, or
2. ${\displaystyle a}$  is assigned F.

For the pair ${\displaystyle a}$ , ${\displaystyle b}$  there are ${\displaystyle 2^{2}=4}$  possible interpretations:

1. both are assigned T,
2. both are assigned F,
3. ${\displaystyle a}$  is assigned T and ${\displaystyle b}$  is assigned F, or
4. ${\displaystyle a}$  is assigned F and ${\displaystyle b}$  is assigned T.^[14]

Since ${\displaystyle {\mathcal {P}}}$  has ${\displaystyle \aleph _{0}}$ , that is, denumerably many propositional symbols, there are ${\displaystyle 2^{\aleph _{0}}={\mathfrak {c}}}$ , and therefore uncountably many distinct possible interpretations of ${\displaystyle {\mathcal {P}}}$ .^[14]

Interpretation of a sentence of truth-functional propositional logic

Main article: Interpretation (logic)

If φ and ψ are formulas of ${\displaystyle {\mathcal {P}}}$  and ${\displaystyle {\mathcal {I}}}$  is an interpretation of ${\displaystyle {\mathcal {P}}}$  then the following definitions apply:

• A sentence of propositional logic is true under an interpretation ${\displaystyle {\mathcal {I}}}$  if ${\displaystyle {\mathcal {I}}}$  assigns the truth value T to that sentence. If a sentence is true under an interpretation, then that interpretation is called a model of that sentence.
• φ is false under an interpretation ${\displaystyle {\mathcal {I}}}$  if φ is not true under ${\displaystyle {\mathcal {I}}}$ .^[14]
• A sentence of propositional logic is logically valid if it is true under every interpretation.

  ${\displaystyle \models }$  φ means that φ is logically valid.

• A sentence ψ of propositional logic is a semantic consequence of a sentence φ if there is no interpretation under which φ is true and ψ is false.
• A sentence of propositional logic is consistent if it is true under at least one interpretation. It is inconsistent if it is not consistent.

Some consequences of these definitions:

• For any given interpretation a given formula is either true or false.^[14]
• No formula is both true and false under the same interpretation.^[14]
• φ is false for a given interpretation iff ${\displaystyle \neg \phi }$  is true for that interpretation; and φ is true under an interpretation iff ${\displaystyle \neg \phi }$  is false under that interpretation.^[14]
• If φ and ${\displaystyle (\phi \to \psi )}$  are both true under a given interpretation, then ψ is true under that interpretation.^[14]
• If ${\displaystyle \models _{\mathrm {P} }\phi }$  and ${\displaystyle \models _{\mathrm {P} }(\phi \to \psi )}$ , then ${\displaystyle \models _{\mathrm {P} }\psi }$ .^[14]
• ${\displaystyle \neg \phi }$  is true under ${\displaystyle {\mathcal {I}}}$  iff φ is not true under ${\displaystyle {\mathcal {I}}}$ .
• ${\displaystyle (\phi \to \psi )}$  is true under ${\displaystyle {\mathcal {I}}}$  iff either φ is not true under ${\displaystyle {\mathcal {I}}}$  or ψ is true under ${\displaystyle {\mathcal {I}}}$ .^[14]
• A sentence ψ of propositional logic is a semantic consequence of a sentence φ iff ${\displaystyle (\phi \to \psi )}$  is logically valid, that is, ${\displaystyle \phi \models _{\mathrm {P} }\psi }$  iff ${\displaystyle \models _{\mathrm {P} }(\phi \to \psi )}$ .^[14]

Alternative calculus

It is possible to define another version of propositional calculus, which defines most of the syntax of the logical operators by means of axioms, and which uses only one inference rule.

Axioms

Let φ, χ, and ψ stand for well-formed formulas. (The well-formed formulas themselves would not contain any Greek letters, but only capital Roman letters, connective operators, and parentheses.) Then the axioms are as follows:

Axioms

Name	Axiom Schema	Description
THEN-1	${\displaystyle \phi \to (\chi \to \phi )}$	Add hypothesis χ, implication introduction
THEN-2	${\displaystyle (\phi \to (\chi \to \psi ))\to ((\phi \to \chi )\to (\phi \to \psi ))}$	Distribute hypothesis ${\displaystyle \phi }$  over implication
AND-1	${\displaystyle \phi \land \chi \to \phi }$	Eliminate conjunction
AND-2	${\displaystyle \phi \land \chi \to \chi }$
AND-3	${\displaystyle \phi \to (\chi \to (\phi \land \chi ))}$	Introduce conjunction
OR-1	${\displaystyle \phi \to \phi \lor \chi }$	Introduce disjunction
OR-2	${\displaystyle \chi \to \phi \lor \chi }$
OR-3	${\displaystyle (\phi \to \psi )\to ((\chi \to \psi )\to (\phi \lor \chi \to \psi ))}$	Eliminate disjunction
NOT-1	${\displaystyle (\phi \to \chi )\to ((\phi \to \neg \chi )\to \neg \phi )}$	Introduce negation
NOT-2	${\displaystyle \phi \to (\neg \phi \to \chi )}$	Eliminate negation
NOT-3	${\displaystyle \phi \lor \neg \phi }$	Excluded middle, classical logic
IFF-1	${\displaystyle (\phi \leftrightarrow \chi )\to (\phi \to \chi )}$	Eliminate equivalence
IFF-2	${\displaystyle (\phi \leftrightarrow \chi )\to (\chi \to \phi )}$
IFF-3	${\displaystyle (\phi \to \chi )\to ((\chi \to \phi )\to (\phi \leftrightarrow \chi ))}$	Introduce equivalence

• Axiom THEN-2 may be considered to be a "distributive property of implication with respect to implication."
• Axioms AND-1 and AND-2 correspond to "conjunction elimination". The relation between AND-1 and AND-2 reflects the commutativity of the conjunction operator.
• Axiom AND-3 corresponds to "conjunction introduction."
• Axioms OR-1 and OR-2 correspond to "disjunction introduction." The relation between OR-1 and OR-2 reflects the commutativity of the disjunction operator.
• Axiom NOT-1 corresponds to "reductio ad absurdum."
• Axiom NOT-2 says that "anything can be deduced from a contradiction."
• Axiom NOT-3 is called "tertium non-datur" (Latin: "a third is not given") and reflects the semantic valuation of propositional formulas: a formula can have a truth-value of either true or false. There is no third truth-value, at least not in classical logic. Intuitionistic logicians do not accept the axiom NOT-3.

Inference rule

The inference rule is modus ponens:

${\displaystyle {\frac {\phi ,\ \phi \to \chi }{\chi }}}$ .

Meta-inference rule

Let a demonstration be represented by a sequence, with hypotheses to the left of the turnstile and the conclusion to the right of the turnstile. Then the deduction theorem can be stated as follows:

If the sequence

${\displaystyle \phi _{1},\ \phi _{2},\ ...,\ \phi _{n},\ \chi \vdash \psi }$ 

has been demonstrated, then it is also possible to demonstrate the sequence

${\displaystyle \phi _{1},\ \phi _{2},\ ...,\ \phi _{n}\vdash \chi \to \psi }$ .

This deduction theorem (DT) is not itself formulated with propositional calculus: it is not a theorem of propositional calculus, but a theorem about propositional calculus. In this sense, it is a meta-theorem, comparable to theorems about the soundnes

December 20, 2023