Set function

In mathematics, especially measure theory, a set function is a function whose domain is a family of subsets of some given set and that (usually) takes its values in the extended real number line ${\displaystyle \mathbb {R} \cup \{\pm \infty \},}$ which consists of the real numbers ${\displaystyle \mathbb {R} }$ and ${\displaystyle \pm \infty .}$

A set function generally aims to measure subsets in some way. Measures are typical examples of "measuring" set functions. Therefore, the term "set function" is often used for avoiding confusion between the mathematical meaning of "measure" and its common language meaning.

Definitions

If ${\displaystyle {\mathcal {F}}}$  is a family of sets over ${\displaystyle \Omega }$  (meaning that ${\displaystyle {\mathcal {F}}\subseteq \wp (\Omega )}$  where ${\displaystyle \wp (\Omega )}$  denotes the powerset) then a set function on ${\displaystyle {\mathcal {F}}}$  is a function ${\displaystyle \mu }$  with domain ${\displaystyle {\mathcal {F}}}$  and codomain ${\displaystyle [-\infty ,\infty ]}$  or, sometimes, the codomain is instead some vector space, as with vector measures, complex measures, and projection-valued measures. The domain of a set function may have any number properties; the commonly encountered properties and categories of families are listed in the table below.

Families ${\displaystyle {\mathcal {F}}}$  of sets over ${\displaystyle \Omega }$  v t e
Is necessarily true of ${\displaystyle {\mathcal {F}}\colon }$  or, is ${\displaystyle {\mathcal {F}}}$  closed under:	Directed by ${\displaystyle \,\supseteq }$	${\displaystyle A\cap B}$	${\displaystyle A\cup B}$	${\displaystyle B\setminus A}$	${\displaystyle \Omega \setminus A}$	${\displaystyle A_{1}\cap A_{2}\cap \cdots }$	${\displaystyle A_{1}\cup A_{2}\cup \cdots }$	${\displaystyle \Omega \in {\mathcal {F}}}$	${\displaystyle \varnothing \in {\mathcal {F}}}$	F.I.P.
π-system
Semiring										Never
Semialgebra (Semifield)										Never
Monotone class						only if ${\displaystyle A_{i}\searrow }$	only if ${\displaystyle A_{i}\nearrow }$
𝜆-system (Dynkin System)				only if ${\displaystyle A\subseteq B}$			only if ${\displaystyle A_{i}\nearrow }$  or they are disjoint			Never
Ring (Order theory)
Ring (Measure theory)										Never
δ-Ring										Never
𝜎-Ring										Never
Algebra (Field)										Never
𝜎-Algebra (𝜎-Field)										Never
Dual ideal
Filter				Never	Never				${\displaystyle \varnothing \not \in {\mathcal {F}}}$
Prefilter (Filter base)				Never	Never				${\displaystyle \varnothing \not \in {\mathcal {F}}}$
Filter subbase				Never	Never				${\displaystyle \varnothing \not \in {\mathcal {F}}}$
Open Topology							(even arbitrary ${\displaystyle \cup }$ )			Never
Closed Topology						(even arbitrary ${\displaystyle \cap }$ )				Never
Is necessarily true of ${\displaystyle {\mathcal {F}}\colon }$  or, is ${\displaystyle {\mathcal {F}}}$  closed under:	directed downward	finite intersections	finite unions	relative complements	complements in ${\displaystyle \Omega }$	countable intersections	countable unions	contains ${\displaystyle \Omega }$	contains ${\displaystyle \varnothing }$	Finite Intersection Property
Additionally, a semiring is a π-system where every complement ${\displaystyle B\setminus A}$  is equal to a finite disjoint union of sets in ${\displaystyle {\mathcal {F}}.}$  A semialgebra is a semiring where every complement ${\displaystyle \Omega \setminus A}$  is equal to a finite disjoint union of sets in ${\displaystyle {\mathcal {F}}.}$  ${\displaystyle A,B,A_{1},A_{2},\ldots }$  are arbitrary elements of ${\displaystyle {\mathcal {F}}}$  and it is assumed that ${\displaystyle {\mathcal {F}}\neq \varnothing .}$

In general, it is typically assumed that ${\displaystyle \mu (E)+\mu (F)}$  is always well-defined for all ${\displaystyle E,F\in {\mathcal {F}},}$  or equivalently, that ${\displaystyle \mu }$  does not take on both ${\displaystyle -\infty }$  and ${\displaystyle +\infty }$  as values. This article will henceforth assume this; although alternatively, all definitions below could instead be qualified by statements such as "whenever the sum/series is defined". This is sometimes done with subtraction, such as with the following result, which holds whenever ${\displaystyle \mu }$  is finitely additive:

Set difference formula: ${\displaystyle \mu (F)-\mu (E)=\mu (F\setminus E){\text{ whenever }}\mu (F)-\mu (E)}$  is defined with ${\displaystyle E,F\in {\mathcal {F}}}$  satisfying ${\displaystyle E\subseteq F}$  and ${\displaystyle F\setminus E\in {\mathcal {F}}.}$ 

Null sets

A set ${\displaystyle F\in {\mathcal {F}}}$  is called a null set (with respect to ${\displaystyle \mu }$ ) or simply null if ${\displaystyle \mu (F)=0.}$  Whenever ${\displaystyle \mu }$  is not identically equal to either ${\displaystyle -\infty }$  or ${\displaystyle +\infty }$  then it is typically also assumed that:

• null empty set: ${\displaystyle \mu (\varnothing )=0}$  if ${\displaystyle \varnothing \in {\mathcal {F}}.}$ 

Variation and mass

The total variation of a set ${\displaystyle S}$  is

$${\displaystyle |\mu |(S)~{\stackrel {\scriptscriptstyle {\text{def}}}{=}}~\sup\{|\mu (F)|:F\in {\mathcal {F}}{\text{ and }}F\subseteq S\}}$$

 

where ${\displaystyle |\,\cdot \,|}$  denotes the absolute value (or more generally, it denotes the norm or seminorm if ${\displaystyle \mu }$  is vector-valued in a (semi)normed space). Assuming that ${\displaystyle \cup {\mathcal {F}}~{\stackrel {\scriptscriptstyle {\text{def}}}{=}}~\textstyle \bigcup \limits _{F\in {\mathcal {F}}}F\in {\mathcal {F}},}$  then ${\displaystyle |\mu |\left(\cup {\mathcal {F}}\right)}$  is called the total variation of ${\displaystyle \mu }$  and ${\displaystyle \mu \left(\cup {\mathcal {F}}\right)}$  is called the mass of ${\displaystyle \mu .}$ 

A set function is called finite if for every ${\displaystyle F\in {\mathcal {F}},}$  the value ${\displaystyle \mu (F)}$  is finite (which by definition means that ${\displaystyle \mu (F)\neq \infty }$  and ${\displaystyle \mu (F)\neq -\infty }$ ; an infinite value is one that is equal to ${\displaystyle \infty }$  or ${\displaystyle -\infty }$ ). Every finite set function must have a finite mass.

Common properties of set functions

A set function ${\displaystyle \mu }$  on ${\displaystyle {\mathcal {F}}}$  is said to be^[1]

• non-negative if it is valued in ${\displaystyle [0,\infty ].}$ 
• finitely additive if ${\displaystyle \textstyle \sum \limits _{i=1}^{n}\mu \left(F_{i}\right)=\mu \left(\textstyle \bigcup \limits _{i=1}^{n}F_{i}\right)}$  for all pairwise disjoint finite sequences ${\displaystyle F_{1},\ldots ,F_{n}\in {\mathcal {F}}}$  such that ${\displaystyle \textstyle \bigcup \limits _{i=1}^{n}F_{i}\in {\mathcal {F}}.}$ 
  • If ${\displaystyle {\mathcal {F}}}$  is closed under binary unions then ${\displaystyle \mu }$  is finitely additive if and only if ${\displaystyle \mu (E\cup F)=\mu (E)+\mu (F)}$  for all disjoint pairs ${\displaystyle E,F\in {\mathcal {F}}.}$ 
  • If ${\displaystyle \mu }$  is finitely additive and if ${\displaystyle \varnothing \in {\mathcal {F}}}$  then taking ${\displaystyle E:=F:=\varnothing }$  shows that ${\displaystyle \mu (\varnothing )=\mu (\varnothing )+\mu (\varnothing )}$  which is only possible if ${\displaystyle \mu (\varnothing )=0}$  or ${\displaystyle \mu (\varnothing )=\pm \infty ,}$  where in the latter case, ${\displaystyle \mu (E)=\mu (E\cup \varnothing )=\mu (E)+\mu (\varnothing )=\mu (E)+(\pm \infty )=\pm \infty }$  for every ${\displaystyle E\in {\mathcal {F}}}$  (so only the case ${\displaystyle \mu (\varnothing )=0}$  is useful).
• countably additive or σ-additive^[2] if in addition to being finitely additive, for all pairwise disjoint sequences ${\displaystyle F_{1},F_{2},\ldots \,}$  in ${\displaystyle {\mathcal {F}}}$  such that ${\displaystyle \textstyle \bigcup \limits _{i=1}^{\infty }F_{i}\in {\mathcal {F}},}$  all of the following hold:
  1. ${\displaystyle \textstyle \sum \limits _{i=1}^{\infty }\mu \left(F_{i}\right)=\mu \left(\textstyle \bigcup \limits _{i=1}^{\infty }F_{i}\right)}$ 
     • The series on the left hand side is defined in the usual way as the limit ${\displaystyle \textstyle \sum \limits _{i=1}^{\infty }\mu \left(F_{i}\right)~{\stackrel {\scriptscriptstyle {\text{def}}}{=}}~{\displaystyle \lim _{n\to \infty }}\mu \left(F_{1}\right)+\cdots +\mu \left(F_{n}\right).}$ 
     • As a consequence, if ${\displaystyle \rho :\mathbb {N} \to \mathbb {N} }$  is any permutation/bijection then ${\displaystyle \textstyle \sum \limits _{i=1}^{\infty }\mu \left(F_{i}\right)=\textstyle \sum \limits _{i=1}^{\infty }\mu \left(F_{\rho (i)}\right);}$  this is because ${\displaystyle \textstyle \bigcup \limits _{i=1}^{\infty }F_{i}=\textstyle \bigcup \limits _{i=1}^{\infty }F_{\rho (i)}}$  and applying this condition (a) twice guarantees that both ${\displaystyle \textstyle \sum \limits _{i=1}^{\infty }\mu \left(F_{i}\right)=\mu \left(\textstyle \bigcup \limits _{i=1}^{\infty }F_{i}\right)}$  and ${\displaystyle \mu \left(\textstyle \bigcup \limits _{i=1}^{\infty }F_{\rho (i)}\right)=\textstyle \sum \limits _{i=1}^{\infty }\mu \left(F_{\rho (i)}\right)}$  hold. By definition, a convergent series with this property is said to be unconditionally convergent. Stated in plain English, this means that rearranging/relabeling the sets ${\displaystyle F_{1},F_{2},\ldots }$  to the new order ${\displaystyle F_{\rho (1)},F_{\rho (2)},\ldots }$  does not affect the sum of their measures. This is desirable since just as the union ${\displaystyle F~{\stackrel {\scriptscriptstyle {\text{def}}}{=}}~\textstyle \bigcup \limits _{i\in \mathbb {N} }F_{i}}$  does not depend on the order of these sets, the same should be true of the sums ${\displaystyle \mu (F)=\mu \left(F_{1}\right)+\mu \left(F_{2}\right)+\cdots }$  and ${\displaystyle \mu (F)=\mu \left(F_{\rho (1)}\right)+\mu \left(F_{\rho (2)}\right)+\cdots \,.}$ 
  2. if ${\displaystyle \mu \left(\textstyle \bigcup \limits _{i=1}^{\infty }F_{i}\right)}$  is not infinite then this series ${\displaystyle \textstyle \sum \limits _{i=1}^{\infty }\mu \left(F_{i}\right)}$  must also converge absolutely, which by definition means that ${\displaystyle \textstyle \sum \limits _{i=1}^{\infty }\left|\mu \left(F_{i}\right)\right|}$  must be finite. This is automatically true if ${\displaystyle \mu }$  is non-negative (or even just valued in the extended real numbers).
     • As with any convergent series of real numbers, by the Riemann series theorem, the series ${\displaystyle \textstyle \sum \limits _{i=1}^{\infty }\mu \left(F_{i}\right)={\displaystyle \lim _{N\to \infty }}\mu \left(F_{1}\right)+\mu \left(F_{2}\right)+\cdots +\mu \left(F_{N}\right)}$  converges absolutely if and only if its sum does not depend on the order of its terms (a property known as unconditional convergence). Since unconditional convergence is guaranteed by (a) above, this condition is automatically true if ${\displaystyle \mu }$  is valued in ${\displaystyle [-\infty ,\infty ].}$ 
  3. if ${\displaystyle \mu \left(\textstyle \bigcup \limits _{i=1}^{\infty }F_{i}\right)=\textstyle \sum \limits _{i=1}^{\infty }\mu \left(F_{i}\right)}$  is infinite then it is also required that the value of at least one of the series ${\displaystyle \textstyle \sum \limits _{\stackrel {i\in \mathbb {N} }{\mu \left(F_{i}\right)>0}}\mu \left(F_{i}\right)\;{\text{ and }}\;\textstyle \sum \limits _{\stackrel {i\in \mathbb {N} }{\mu \left(F_{i}\right)<0}}\mu \left(F_{i}\right)\;}$  be finite (so that the sum of their values is well-defined). This is automatically true if ${\displaystyle \mu }$  is non-negative.
• a pre-measure if it is non-negative, countably additive (including finitely additive), and has a null empty set.
• a measure if it is a pre-measure whose domain is a σ-algebra. That is to say, a measure is a non-negative countably additive set function on a σ-algebra that has a null empty set.
• a probability measure if it is a measure that has a mass of ${\displaystyle 1.}$ 
• an outer measure if it is non-negative, countably subadditive, has a null empty set, and has the power set ${\displaystyle \wp (\Omega )}$  as its domain.
  • Outer measures appear in the Carathéodory's extension theorem and they are often restricted to Carathéodory measurable subsets
• a signed measure if it is countably additive, has a null empty set, and ${\displaystyle \mu }$  does not take on both ${\displaystyle -\infty }$  and ${\displaystyle +\infty }$  as values.
• complete if every subset of every null set is null; explicitly, this means: whenever ${\displaystyle F\in {\mathcal {F}}{\text{ satisfies }}\mu (F)=0}$  and ${\displaystyle N\subseteq F}$  is any subset of ${\displaystyle F}$  then ${\displaystyle N\in {\mathcal {F}}}$  and ${\displaystyle \mu (N)=0.}$ 
  • Unlike many other properties, completeness places requirements on the set ${\displaystyle \operatorname {domain} \mu ={\mathcal {F}}}$  (and not just on ${\displaystyle \mu }$ 's values).
• 𝜎-finite if there exists a sequence ${\displaystyle F_{1},F_{2},F_{3},\ldots \,}$  in ${\displaystyle {\mathcal {F}}}$  such that ${\displaystyle \mu \left(F_{i}\right)}$  is finite for every index ${\displaystyle i,}$  and also ${\displaystyle \textstyle \bigcup \limits _{n=1}^{\infty }F_{n}=\textstyle \bigcup \limits _{F\in {\mathcal {F}}}F.}$ 
• decomposable if there exists a subfamily ${\displaystyle {\mathcal {P}}\subseteq {\mathcal {F}}}$  of pairwise disjoint sets such that ${\displaystyle \mu (P)}$  is finite for every ${\displaystyle P\in {\mathcal {P}}}$  and also ${\displaystyle \textstyle \bigcup \limits _{P\in {\mathcal {P}}}\,P=\textstyle \bigcup \limits _{F\in {\mathcal {F}}}F}$  (where ${\displaystyle {\mathcal {F}}=\operatorname {domain} \mu }$ ).
  • Every 𝜎-finite set function is decomposable although not conversely. For example, the counting measure on ${\displaystyle \mathbb {R} }$  (whose domain is ${\displaystyle \wp (\mathbb {R} )}$ ) is decomposable but not 𝜎-finite.
• a vector measure if it is a countably additive set function ${\displaystyle \mu :{\mathcal {F}}\to X}$  valued in a topological vector space ${\displaystyle X}$  (such as a normed space) whose domain is a σ-algebra.
  • If ${\displaystyle \mu }$  is valued in a normed space ${\displaystyle (X,\|\cdot \|)}$  then it is countably additive if and only if for any pairwise disjoint sequence ${\displaystyle F_{1},F_{2},\ldots \,}$  in ${\displaystyle {\mathcal {F}},}$  ${\displaystyle \lim _{n\to \infty }\left\|\mu \left(F_{1}\right)+\cdots +\mu \left(F_{n}\right)-\mu \left(\textstyle \bigcup \limits _{i=1}^{\infty }F_{i}\right)\right\|=0.}$  If ${\displaystyle \mu }$  is finitely additive and valued in a Banach space then it is countably additive if and only if for any pairwise disjoint sequence ${\displaystyle F_{1},F_{2},\ldots \,}$  in ${\displaystyle {\mathcal {F}},}$  ${\displaystyle \lim _{n\to \infty }\left\|\mu \left(F_{n}\cup F_{n+1}\cup F_{n+2}\cup \cdots \right)\right\|=0.}$ 
• a complex measure if it is a countably additive complex-valued set function ${\displaystyle \mu :{\mathcal {F}}\to \mathbb {C} }$  whose domain is a σ-algebra.
  • By definition, a complex measure never takes ${\displaystyle \pm \infty }$  as a value and so has a null empty set.
• a random measure if it is a measure-valued random element.

Arbitrary sums

As described in this article's section on generalized series, for any family ${\displaystyle \left(r_{i}\right)_{i\in I}}$  of real numbers indexed by an arbitrary indexing set ${\displaystyle I,}$  it is possible to define their sum ${\displaystyle \textstyle \sum \limits _{i\in I}r_{i}}$  as the limit of the net of finite partial sums ${\displaystyle F\in \operatorname {FiniteSubsets} (I)\mapsto \textstyle \sum \limits _{i\in F}r_{i}}$  where the domain ${\displaystyle \operatorname {FiniteSubsets} (I)}$  is directed by ${\displaystyle \,\subseteq .\,}$  Whenever this net converges then its limit is denoted by the symbols ${\displaystyle \textstyle \sum \limits _{i\in I}r_{i}}$  while if this net instead diverges to ${\displaystyle \pm \infty }$  then this may be indicated by writing ${\displaystyle \textstyle \sum \limits _{i\in I}r_{i}=\pm \infty .}$  Any sum over the empty set is defined to be zero; that is, if ${\displaystyle I=\varnothing }$  then ${\displaystyle \textstyle \sum \limits _{i\in \varnothing }r_{i}=0}$  by definition.

For example, if ${\displaystyle z_{i}=0}$  for every ${\displaystyle i\in I}$  then ${\displaystyle \textstyle \sum \limits _{i\in I}z_{i}=0.}$  And it can be shown that ${\displaystyle \textstyle \sum \limits _{i\in I}r_{i}=\textstyle \sum \limits _{\stackrel {i\in I,}{r_{i}=0}}r_{i}+\textstyle \sum \limits _{\stackrel {i\in I,}{r_{i}\neq 0}}r_{i}=0+\textstyle \sum \limits _{\stackrel {i\in I,}{r_{i}\neq 0}}r_{i}=\textstyle \sum \limits _{\stackrel {i\in I,}{r_{i}\neq 0}}r_{i}.}$  If ${\displaystyle I=\mathbb {N} }$  then the generalized series ${\displaystyle \textstyle \sum \limits _{i\in I}r_{i}}$  converges in ${\displaystyle \mathbb {R} }$  if and only if ${\displaystyle \textstyle \sum \limits _{i=1}^{\infty }r_{i}}$  converges unconditionally (or equivalently, converges absolutely) in the usual sense. If a generalized series ${\displaystyle \textstyle \sum \limits _{i\in I}r_{i}}$  converges in ${\displaystyle \mathbb {R} }$  then both ${\displaystyle \textstyle \sum \limits _{\stackrel {i\in I}{r_{i}>0}}r_{i}}$  and ${\displaystyle \textstyle \sum \limits _{\stackrel {i\in I}{r_{i}<0}}r_{i}}$  also converge to elements of ${\displaystyle \mathbb {R} }$  and the set ${\displaystyle \left\{i\in I:r_{i}\neq 0\right\}}$  is necessarily countable (that is, either finite or countably infinite); this remains true if ${\displaystyle \mathbb {R} }$  is replaced with any normed space.^{[proof 1]} It follows that in order for a generalized series ${\displaystyle \textstyle \sum \limits _{i\in I}r_{i}}$  to converge in ${\displaystyle \mathbb {R} }$  or ${\displaystyle \mathbb {C} ,}$  it is necessary that all but at most countably many ${\displaystyle r_{i}}$  will be equal to ${\displaystyle 0,}$  which means that ${\displaystyle \textstyle \sum \limits _{i\in I}r_{i}~=~\textstyle \sum \limits _{\stackrel {i\in I}{r_{i}\neq 0}}r_{i}}$  is a sum of at most countably many non-zero terms. Said differently, if ${\displaystyle \left\{i\in I:r_{i}\neq 0\right\}}$  is uncountable then the generalized series ${\displaystyle \textstyle \sum \limits _{i\in I}r_{i}}$  does not converge.

In summary, due to the nature of the real numbers and its topology, every generalized series of real numbers (indexed by an arbitrary set) that converges can be reduced to an ordinary absolutely convergent series of countably many real numbers. So in the context of measure theory, there is little benefit gained by considering uncountably many sets and generalized series. In particular, this is why the definition of "countably additive" is rarely extended from countably many sets ${\displaystyle F_{1},F_{2},\ldots \,}$  in ${\displaystyle {\mathcal {F}}}$  (and the usual countable series ${\displaystyle \textstyle \sum \limits _{i=1}^{\infty }\mu \left(F_{i}\right)}$ ) to arbitrarily many sets ${\displaystyle \left(F_{i}\right)_{i\in I}}$  (and the generalized series ${\displaystyle \textstyle \sum \limits _{i\in I}\mu \left(F_{i}\right)}$ ).

Inner measures, outer measures, and other properties

A set function ${\displaystyle \mu }$  is said to be/satisfies^[1]

• monotone if ${\displaystyle \mu (E)\leq \mu (F)}$  whenever ${\displaystyle E,F\in {\mathcal {F}}}$  satisfy ${\displaystyle E\subseteq F.}$ 
• modular if it satisfies the following condition, known as modularity: ${\displaystyle \mu (E\cup F)+\mu (E\cap F)=\mu (E)+\mu (F)}$  for all ${\displaystyle E,F\in {\mathcal {F}}}$  such that ${\displaystyle E\cup F,E\cap F\in {\mathcal {F}}.}$ 
  • Every finitely additive function on a field of sets is modular.
  • In geometry, a set function valued in some abelian semigroup that possess this property is known as a valuation. This geometric definition of "valuation" should not be confused with the stronger non-equivalent measure theoretic definition of "valuation" that is given below.
• submodular if ${\displaystyle \mu (E\cup F)+\mu (E\cap F)\leq \mu (E)+\mu (F)}$  for all ${\displaystyle E,F\in {\mathcal {F}}}$  such that ${\displaystyle E\cup F,E\cap F\in {\mathcal {F}}.}$ 
• finitely subadditive if ${\displaystyle |\mu (F)|\leq \textstyle \sum \limits _{i=1}^{n}\left|\mu \left(F_{i}\right)\right|}$  for all finite sequences ${\displaystyle F,F_{1},\ldots ,F_{n}\in {\mathcal {F}}}$  that satisfy ${\displaystyle F\;\subseteq \;\textstyle \bigcup \limits _{i=1}^{n}F_{i}.}$ 
• countably subadditive or σ-subadditive if ${\displaystyle |\mu (F)|\leq \textstyle \sum \limits _{i=1}^{\infty }\left|\mu \left(F_{i}\right)\right|}$  for all sequences ${\displaystyle F,F_{1},F_{2},F_{3},\ldots \,}$  in ${\displaystyle {\mathcal {F}}}$  that satisfy ${\displaystyle F\;\subseteq \;\textstyle \bigcup \limits _{i=1}^{\infty }F_{i}.}$ 
  • If ${\displaystyle {\mathcal {F}}}$  is closed under finite unions then this condition holds if and only if ${\displaystyle |\mu (F\cup G)|\leq |\mu (F)|+|\mu (G)|}$  for all ${\displaystyle F,G\in {\mathcal {F}}.}$  If ${\displaystyle \mu }$  is non-negative then the absolute values may be removed.
  • If ${\displaystyle \mu }$  is a measure then this condition holds if and only if ${\displaystyle \mu \left(\textstyle \bigcup \limits _{i=1}^{\infty }F_{i}\right)\leq \textstyle \sum \limits _{i=1}^{\infty }\mu \left(F_{i}\right)}$  for all ${\displaystyle F_{1},F_{2},F_{3},\ldots \,}$  in ${\displaystyle {\mathcal {F}}.}$ ^[3] If ${\displaystyle \mu }$  is a probability measure then this inequality is Boole's inequality.
  • If ${\displaystyle \mu }$  is countably subadditive and ${\displaystyle \varnothing \in {\mathcal {F}}}$  with ${\displaystyle \mu (\varnothing )=0}$  then ${\displaystyle \mu }$  is finitely subadditive.
• superadditive if ${\displaystyle \mu (E)+\mu (F)\leq \mu (E\cup F)}$  whenever ${\displaystyle E,F\in {\mathcal {F}}}$  are disjoint with ${\displaystyle E\cup F\in {\mathcal {F}}.}$ 
• continuous from above if ${\displaystyle \lim _{n\to \infty }\mu \left(F_{i}\right)=\mu \left(\textstyle \bigcap \limits _{i=1}^{\infty }F_{i}\right)}$  for all non-increasing sequences of sets ${\displaystyle F_{1}\supseteq F_{2}\supseteq F_{3}\cdots \,}$  in ${\displaystyle {\mathcal {F}}}$  such that ${\displaystyle \textstyle \bigcap \limits _{i=1}^{\infty }F_{i}\in {\mathcal {F}}}$  with ${\displaystyle \mu \left(\textstyle \bigcap \limits _{i=1}^{\infty }F_{i}\right)}$  and all ${\displaystyle \mu \left(F_{i}\right)}$  finite.
  • Lebesgue measure ${\displaystyle \lambda }$  is continuous from above but it would not be if the assumption that all ${\displaystyle \mu \left(F_{i}\right)}$  are eventually finite was omitted from the definition, as this example shows: For every integer ${\displaystyle i,}$  let ${\displaystyle F_{i}}$  be the open interval ${\displaystyle (i,\infty )}$  so that ${\displaystyle \lim _{n\to \infty }\lambda \left(F_{i}\right)=\lim _{n\to \infty }\infty =\infty \neq 0=\lambda (\varnothing )=\lambda \left(\textstyle \bigcap \limits _{i=1}^{\infty }F_{i}\right)}$  where ${\displaystyle \textstyle \bigcap \limits _{i=1}^{\infty }F_{i}=\varnothing .}$ 
• continuous from below if ${\displaystyle \lim _{n\to \infty }\mu \left(F_{i}\right)=\mu \left(\textstyle \bigcup \limits _{i=1}^{\infty }F_{i}\right)}$  for all non-decreasing sequences of sets ${\displaystyle F_{1}\subseteq F_{2}\subseteq F_{3}\cdots \,}$  in ${\displaystyle {\mathcal {F}}}$  such that ${\displaystyle \textstyle \bigcup \limits _{i=1}^{\infty }F_{i}\in {\mathcal {F}}.}$ 
• infinity is approached from below if whenever ${\displaystyle F\in {\mathcal {F}}}$  satisfies ${\displaystyle \mu (F)=\infty }$  then for every real ${\displaystyle r>0,}$  there exists some ${\displaystyle F_{r}\in {\mathcal {F}}}$  such that ${\displaystyle F_{r}\subseteq F}$  and ${\displaystyle r\leq \mu \left(F_{r}\right)<\infty .}$ 
• an outer measure if ${\displaystyle \mu }$  is non-negative, countably subadditive, has a null empty set, and has the power set ${\displaystyle \wp (\Omega )}$  as its domain.
• an inner measure if ${\displaystyle \mu }$  is non-negative, superadditive, continuous from above, has a null empty set, has the power set ${\displaystyle \wp (\Omega )}$  as its domain, and ${\displaystyle +\infty }$  is approached from below.
• atomic if every measurable set of positive measure contains an atom.

If a binary operation ${\displaystyle \,+\,}$

December 26, 2023