Harmonic number

For other uses, see Harmonic number (disambiguation).

In mathematics, the n-th harmonic number is the sum of the reciprocals of the first n natural numbers:

The harmonic number ${\displaystyle H_{n}}$ with ${\displaystyle n=\lfloor x\rfloor }$ (red line) with its asymptotic limit ${\displaystyle \gamma +\ln(x)}$ (blue line) where ${\displaystyle \gamma }$ is the Euler–Mascheroni constant.

$${\displaystyle H_{n}=1+{\frac {1}{2}}+{\frac {1}{3}}+\cdots +{\frac {1}{n}}=\sum _{k=1}^{n}{\frac {1}{k}}.}$$

Starting from n = 1, the sequence of harmonic numbers begins:

$${\displaystyle 1,{\frac {3}{2}},{\frac {11}{6}},{\frac {25}{12}},{\frac {137}{60}},\dots }$$

Harmonic numbers are related to the harmonic mean in that the n-th harmonic number is also n times the reciprocal of the harmonic mean of the first n positive integers.

Harmonic numbers have been studied since antiquity and are important in various branches of number theory. They are sometimes loosely termed harmonic series, are closely related to the Riemann zeta function, and appear in the expressions of various special functions.

The harmonic numbers roughly approximate the natural logarithm function^[1]: 143 and thus the associated harmonic series grows without limit, albeit slowly. In 1737, Leonhard Euler used the divergence of the harmonic series to provide a new proof of the infinity of prime numbers. His work was extended into the complex plane by Bernhard Riemann in 1859, leading directly to the celebrated Riemann hypothesis about the distribution of prime numbers.

When the value of a large quantity of items has a Zipf's law distribution, the total value of the n most-valuable items is proportional to the n-th harmonic number. This leads to a variety of surprising conclusions regarding the long tail and the theory of network value.

The Bertrand-Chebyshev theorem implies that, except for the case n = 1, the harmonic numbers are never integers.^[2]

The first 40 harmonic numbers

n	Harmonic number, Hn
	expressed as a fraction		decimal	relative size
1	1		1	1
2	3	/2	1.5	1.5
3	11	/6	~1.83333	1.83333
4	25	/12	~2.08333	2.08333
5	137	/60	~2.28333	2.28333
6	49	/20	2.45	2.45
7	363	/140	~2.59286	2.59286
8	761	/280	~2.71786	2.71786
9	7 129	/2 520	~2.82897	2.82897
10	7 381	/2 520	~2.92897	2.92897
11	83 711	/27 720	~3.01988	3.01988
12	86 021	/27 720	~3.10321	3.10321
13	1 145 993	/360 360	~3.18013	3.18013
14	1 171 733	/360 360	~3.25156	3.25156
15	1 195 757	/360 360	~3.31823	3.31823
16	2 436 559	/720 720	~3.38073	3.38073
17	42 142 223	/12 252 240	~3.43955	3.43955
18	14 274 301	/4 084 080	~3.49511	3.49511
19	275 295 799	/77 597 520	~3.54774	3.54774
20	55 835 135	/15 519 504	~3.59774	3.59774
21	18 858 053	/5 173 168	~3.64536	3.64536
22	19 093 197	/5 173 168	~3.69081	3.69081
23	444 316 699	/118 982 864	~3.73429	3.73429
24	1 347 822 955	/356 948 592	~3.77596	3.77596
25	34 052 522 467	/8 923 714 800	~3.81596	3.81596
26	34 395 742 267	/8 923 714 800	~3.85442	3.85442
27	312 536 252 003	/80 313 433 200	~3.89146	3.89146
28	315 404 588 903	/80 313 433 200	~3.92717	3.92717
29	9 227 046 511 387	/2 329 089 562 800	~3.96165	3.96165
30	9 304 682 830 147	/2 329 089 562 800	~3.99499	3.99499
31	290 774 257 297 357	/72 201 776 446 800	~4.02725	4.02725
32	586 061 125 622 639	/144 403 552 893 600	~4.05850	4.0585
33	53 676 090 078 349	/13 127 595 717 600	~4.08880	4.0888
34	54 062 195 834 749	/13 127 595 717 600	~4.11821	4.11821
35	54 437 269 998 109	/13 127 595 717 600	~4.14678	4.14678
36	54 801 925 434 709	/13 127 595 717 600	~4.17456	4.17456
37	2 040 798 836 801 833	/485 721 041 551 200	~4.20159	4.20159
38	2 053 580 969 474 233	/485 721 041 551 200	~4.22790	4.2279
39	2 066 035 355 155 033	/485 721 041 551 200	~4.25354	4.25354
40	2 078 178 381 193 813	/485 721 041 551 200	~4.27854	4.27854

Identities involving harmonic numbers

By definition, the harmonic numbers satisfy the recurrence relation

$${\displaystyle H_{n+1}=H_{n}+{\frac {1}{n+1}}.}$$

 

The harmonic numbers are connected to the Stirling numbers of the first kind by the relation

$${\displaystyle H_{n}={\frac {1}{n!}}\left[{n+1 \atop 2}\right].}$$

 

The functions

$${\displaystyle f_{n}(x)={\frac {x^{n}}{n!}}(\log x-H_{n})}$$

 

satisfy the property

$${\displaystyle f_{n}'(x)=f_{n-1}(x).}$$

 

In particular

$${\displaystyle f_{1}(x)=x(\log x-1)}$$

 

is an integral of the logarithmic function.

The harmonic numbers satisfy the series identities

$${\displaystyle \sum _{k=1}^{n}H_{k}=(n+1)H_{n}-n}$$

 

and

$${\displaystyle \sum _{k=1}^{n}H_{k}^{2}=(n+1)H_{n}^{2}-(2n+1)H_{n}+2n.}$$

 

These two results are closely analogous to the corresponding integral results

$${\displaystyle \int _{0}^{x}\log y\ dy=x\log x-x}$$

 

and

$${\displaystyle \int _{0}^{x}(\log y)^{2}\ dy=x(\log x)^{2}-2x\log x+2x.}$$

 

Identities involving π

There are several infinite summations involving harmonic numbers and powers of π:^{[3][better source needed]}

$${\displaystyle \sum _{n=1}^{\infty }{\frac {H_{n}}{n\cdot 2^{n}}}={\frac {1}{12}}\pi ^{2}}$$

 

$${\displaystyle \sum _{n=1}^{\infty }{\frac {H_{n}^{2}}{(n+1)^{2}}}={\frac {11}{360}}\pi ^{4}}$$

 

$${\displaystyle \sum _{n=1}^{\infty }{\frac {H_{n}^{2}}{n^{2}}}={\frac {17}{360}}\pi ^{4}}$$

 

$${\displaystyle \sum _{n=1}^{\infty }{\frac {H_{n}}{n^{3}}}={\frac {1}{72}}\pi ^{4}}$$

 

Calculation

An integral representation given by Euler^[4] is

$${\displaystyle H_{n}=\int _{0}^{1}{\frac {1-x^{n}}{1-x}}\,dx.}$$

 

The equality above is straightforward by the simple algebraic identity

$${\displaystyle {\frac {1-x^{n}}{1-x}}=1+x+\cdots +x^{n-1}.}$$

 

Using the substitution x = 1 − u, another expression for H_n is

$${\displaystyle {\begin{aligned}H_{n}&=\int _{0}^{1}{\frac {1-x^{n}}{1-x}}\,dx=\int _{0}^{1}{\frac {1-(1-u)^{n}}{u}}\,du\\[6pt]&=\int _{0}^{1}\left[-\sum _{k=1}^{n}(-1)^{k}{\binom {n}{k}}u^{k-1}\right]\,du=-\sum _{k=1}^{n}(-1)^{k}{\binom {n}{k}}\int _{0}^{1}u^{k-1}\,du\\[6pt]&=-\sum _{k=1}^{n}(-1)^{k}{\frac {1}{k}}{\binom {n}{k}}.\end{aligned}}}$$

 

 

Graph demonstrating a connection between harmonic numbers and the natural logarithm. The harmonic number H_n can be interpreted as a Riemann sum of the integral: ${\displaystyle \int _{1}^{n+1}{\frac {dx}{x}}=\ln(n+1).}$ 

The nth harmonic number is about as large as the natural logarithm of n. The reason is that the sum is approximated by the integral

$${\displaystyle \int _{1}^{n}{\frac {1}{x}}\,dx,}$$

 

whose value is ln n.

The values of the sequence H_n − ln n decrease monotonically towards the limit

$${\displaystyle \lim _{n\to \infty }\left(H_{n}-\ln n\right)=\gamma ,}$$

 

where γ ≈ 0.5772156649 is the Euler–Mascheroni constant. The corresponding asymptotic expansion is

$${\displaystyle {\begin{aligned}H_{n}&\sim \ln {n}+\gamma +{\frac {1}{2n}}-\sum _{k=1}^{\infty }{\frac {B_{2k}}{2kn^{2k}}}\\&=\ln {n}+\gamma +{\frac {1}{2n}}-{\frac {1}{12n^{2}}}+{\frac {1}{120n^{4}}}-\cdots ,\end{aligned}}}$$

 

where B_k are the Bernoulli numbers.

Generating functions

A generating function for the harmonic numbers is

$${\displaystyle \sum _{n=1}^{\infty }z^{n}H_{n}={\frac {-\ln(1-z)}{1-z}},}$$

 

where ln(z) is the natural logarithm. An exponential generating function is

$${\displaystyle \sum _{n=1}^{\infty }{\frac {z^{n}}{n!}}H_{n}=-e^{z}\sum _{k=1}^{\infty }{\frac {1}{k}}{\frac {(-z)^{k}}{k!}}=e^{z}\operatorname {Ein} (z)}$$

 

where Ein(z) is the entire exponential integral. The exponential integral may also be expressed as

$${\displaystyle \operatorname {Ein} (z)=\mathrm {E} _{1}(z)+\gamma +\ln z=\Gamma (0,z)+\gamma +\ln z}$$

 

where Γ(0, z) is the incomplete gamma function.

Arithmetic properties

The harmonic numbers have several interesting arithmetic properties. It is well-known that ${\textstyle H_{n}}$  is an integer if and only if ${\textstyle n=1}$ , a result often attributed to Taeisinger.^[5] Indeed, using 2-adic valuation, it is not difficult to prove that for ${\textstyle n\geq 2}$  the numerator of ${\textstyle H_{n}}$  is an odd number while the denominator of ${\textstyle H_{n}}$  is an even number. More precisely,

$${\displaystyle H_{n}={\frac {1}{2^{\lfloor \log _{2}(n)\rfloor }}}{\frac {a_{n}}{b_{n}}}}$$

 

with some odd integers ${\textstyle a_{n}}$  and ${\textstyle b_{n}}$ .

As a consequence of Wolstenholme's theorem, for any prime number ${\displaystyle p\geq 5}$  the numerator of ${\displaystyle H_{p-1}}$ is divisible by ${\textstyle p^{2}}$ . Furthermore, Eisenstein^[6] proved that for all odd prime number ${\textstyle p}$  it holds

$${\displaystyle H_{(p-1)/2}\equiv -2q_{p}(2){\pmod {p}}}$$

 

where ${\textstyle q_{p}(2)=(2^{p-1}-1)/p}$  is a Fermat quotient, with the consequence that ${\textstyle p}$  divides the numerator of ${\displaystyle H_{(p-1)/2}}$  if and only if ${\textstyle p}$  is a Wieferich prime.

In 1991, Eswarathasan and Levine^[7] defined ${\displaystyle J_{p}}$  as the set of all positive integers ${\displaystyle n}$  such that the numerator of ${\displaystyle H_{n}}$  is divisible by a prime number ${\displaystyle p.}$  They proved that

$${\displaystyle \{p-1,p^{2}-p,p^{2}-1\}\subseteq J_{p}}$$

 

for all prime numbers ${\displaystyle p\geq 5,}$  and they defined harmonic primes to be the primes ${\textstyle p}$  such that ${\displaystyle J_{p}}$  has exactly 3 elements.

Eswarathasan and Levine also conjectured that ${\displaystyle J_{p}}$  is a finite set for all primes ${\displaystyle p,}$  and that there are infinitely many harmonic primes. Boyd^[8] verified that ${\displaystyle J_{p}}$  is finite for all prime numbers up to ${\displaystyle p=547}$  except 83, 127, and 397; and he gave a heuristic suggesting that the density of the harmonic primes in the set of all primes should be ${\displaystyle 1/e}$ . Sanna^[9] showed that ${\displaystyle J_{p}}$  has zero asymptotic density, while Bing-Ling Wu and Yong-Gao Chen^[10] proved that the number of elements of ${\displaystyle J_{p}}$  not exceeding ${\displaystyle x}$  is at most ${\displaystyle 3x^{{\frac {2}{3}}+{\frac {1}{25\log p}}}}$ , for all ${\displaystyle x\geq 1}$ .

Applications

The harmonic numbers appear in several calculation formulas, such as the digamma function

$${\displaystyle \psi (n)=H_{n-1}-\gamma .}$$

 

This relation is also frequently used to define the extension of the harmonic numbers to non-integer n. The harmonic numbers are also frequently used to define γ using the limit introduced earlier:

$${\displaystyle \gamma =\lim _{n\rightarrow \infty }{\left(H_{n}-\ln(n)\right)},}$$

 

although

$${\displaystyle \gamma =\lim _{n\to \infty }{\left(H_{n}-\ln \left(n+{\frac {1}{2}}\right)\right)}}$$

 

converges more quickly.

In 2002, Jeffrey Lagarias proved^[11] that the Riemann hypothesis is equivalent to the statement that

$${\displaystyle \sigma (n)\leq H_{n}+(\log H_{n})e^{H_{n}},}$$

 

is true for every integer n ≥ 1 with strict inequality if n > 1; here σ(n) denotes the sum of the divisors of n.

The eigenvalues of the nonlocal problem

$${\displaystyle \lambda \varphi (x)=\int _{-1}^{1}{\frac {\varphi (x)-\varphi (y)}{|x-y|}}\,dy}$$

 

are given by ${\displaystyle \lambda =2H_{n}}$ , where by convention ${\displaystyle H_{0}=0}$ , and the corresponding eigenfunctions are given by the Legendre polynomials ${\displaystyle \varphi (x)=P_{n}(x)}$ .^[12]

Generalizations

Generalized harmonic numbers

The nth generalized harmonic number of order m is given by

$${\displaystyle H_{n,m}=\sum _{k=1}^{n}{\frac {1}{k^{m}}}.}$$

 

(In some sources, this may also be denoted by ${\textstyle H_{n}^{(m)}}$  or ${\textstyle H_{m}(n).}$ )

The special case m = 0 gives ${\displaystyle H_{n,0}=n.}$  The special case m = 1 reduces to the usual harmonic number:

$${\displaystyle H_{n,1}=H_{n}=\sum _{k=1}^{n}{\frac {1}{k}}.}$$

 

The limit of ${\textstyle H_{n,m}}$  as n → ∞ is finite if m > 1, with the generalized harmonic number bounded by and converging to the Riemann zeta function

$${\displaystyle \lim _{n\rightarrow \infty }H_{n,m}=\zeta (m).}$$

 

The smallest natural number k such that kⁿ does not divide the denominator of generalized harmonic number H(k, n) nor the denominator of alternating generalized harmonic number H′(k, n) is, for n=1, 2, ... :

77, 20, 94556602, 42, 444, 20, 104, 42, 76, 20, 77, 110, 3504, 20, 903, 42, 1107, 20, 104, 42, 77, 20, 2948, 110, 136, 20, 76, 42, 903, 20, 77, 42, 268, 20, 7004, 110, 1752, 20, 19203, 42, 77, 20, 104, 42, 76, 20, 370, 110, 1107, 20, ... (sequence A128670 in the OEIS)

The related sum ${\displaystyle \sum _{k=1}^{n}k^{m}}$  occurs in the study of Bernoulli numbers; the harmonic numbers also appear in the study of Stirling numbers.

Some integrals of generalized harmonic numbers are

$${\displaystyle \int _{0}^{a}H_{x,2}\,dx=a{\frac {\pi ^{2}}{6}}-H_{a}}$$

 

and

$${\displaystyle \int _{0}^{a}H_{x,3}\,dx=aA-{\frac {1}{2}}H_{a,2},}$$

 

where A is Apéry's constant ζ(3), and

$${\displaystyle \sum _{k=1}^{n}H_{k,m}=(n+1)H_{n,m}-H_{n,m-1}{\text{ for }}m\geq 0.}$$

 

Every generalized harmonic number of order m can be written as a function of harmonic numbers of order ${\displaystyle m-1}$  using

$${\displaystyle H_{n,m}=\sum _{k=1}^{n-1}{\frac {H_{k,m-1}}{k(k+1)}}+{\frac {H_{n,m-1}}{n}}}$$

 

  for example: ${\displaystyle H_{4,3}={\frac {H_{1,2}}{1\cdot 2}}+{\frac {H_{2,2}}{2\cdot 3}}+{\frac {H_{3,2}}{3\cdot 4}}+{\frac {H_{4,2}}{4}}}$ 

A generating function for the generalized harmonic numbers is

$${\displaystyle \sum _{n=1}^{\infty }z^{n}H_{n,m}={\frac {\operatorname {Li} _{m}(z)}{1-z}},}$$

 

where ${\displaystyle \operatorname {Li} _{m}(z)}$  is the polylogarithm, and |z| < 1. The generating function given above for m = 1 is a special case of this formula.

A fractional argument for generalized harmonic numbers can be introduced as follows:

For every ${\displaystyle p,q>0}$  integer, and ${\displaystyle m>1}$  integer or not, we have from polygamma functions:

$${\displaystyle H_{q/p,m}=\zeta (m)-p^{m}\sum _{k=1}^{\infty }{\frac {1}{(q+pk)^{m}}}}$$

 

where ${\displaystyle \zeta (m)}$  is the Riemann zeta function. The relevant recurrence relation is

$${\displaystyle H_{a,m}=H_{a-1,m}+{\frac {1}{a^{m}}}.}$$

 

Some special values are

$${\displaystyle H_{{\frac {1}{4}},2}=16-8G-{\tfrac {5}{6}}\pi ^{2}}$$

 

where G is Catalan's constant,

$${\displaystyle H_{{\frac {1}{2}},2}=4-{\tfrac {\pi ^{2}}{3}}}$$

 

$${\displaystyle H_{{\frac {3}{4}},2}=8G+{\tfrac {16}{9}}-{\tfrac {5}{6}}\pi ^{2}}$$

 

$${\displaystyle H_{{\frac {1}{4}},3}=64-27\zeta (3)-\pi ^{3}}$$

 

$${\displaystyle H_{{\frac {1}{2}},3}=8-6\zeta (3)}$$

 

$${\displaystyle H_{{\frac {3}{4}},3}={({\tfrac {4}{3}})}^{3}-27\zeta (3)+\pi ^{3}}$$

 

In the special case that ${\displaystyle p=1}$ , we get

$${\displaystyle H_{n,m}=\zeta (m,1)-\zeta (m,n+1),}$$

 

where ${\displaystyle \zeta (m,n)}$  is the Hurwitz zeta function. This relationship is used to calculate harmonic numbers numerically.

Multiplication formulas

The multiplication theorem applies to harmonic numbers. Using polygamma functions, we obtain

$${\displaystyle H_{2x}={\frac {1}{2}}\left(H_{x}+H_{x-{\frac {1}{2}}}\right)+\ln 2,}$$

 

$${\displaystyle H_{3x}={\frac {1}{3}}\left(H_{x}+H_{x-{\frac {1}{3}}}+H_{x-{\frac {2}{3}}}\right)+\ln 3,}$$

 

or, more generally,

$${\displaystyle H_{nx}={\frac {1}{n}}\left(H_{x}+H_{x-{\frac {1}{n}}}+H_{x-{\frac {2}{n}}}+\cdots +H_{x-{\frac {n-1}{n}}}\right)+\ln n.}$$

 

For generalized harmonic numbers, we have

$${\displaystyle H_{2x,2}={\frac {1}{2}}\left(\zeta (2)+{\frac {1}{2}}\left(H_{x,2}+H_{x-{\frac {1}{2}},2}\right)\right)}$$

 

$${\displaystyle H_{3x,2}={\frac {1}{9}}\left(6\zeta (2)+H_{x,2}+H_{x-{\frac {1}{3}},2}+H_{x-{\frac {2}{3}},2}\right),}$$

 

where ${\displaystyle \zeta (n)}$  is the Riemann zeta function.

Hyperharmonic numbers

The next generalization was discussed by J. H. Conway and R. K. Guy in their 1995 book The Book of Numbers.^[1]: 258 Let

$${\displaystyle H_{n}^{(0)}={\frac {1}{n}}.}$$

 

Then the nth hyperharmonic number of order r (r>0) is defined recursively as

$${\displaystyle H_{n}^{(r)}=\sum _{k=1}^{n}H_{k}^{(r-1)}.}$$

 

In particular, ${\displaystyle H_{n}^{(1)}}$  is the ordinary harmonic number ${\displaystyle H_{n}}$ .

Harmonic numbers for real and complex values

The formulae given above,

$${\displaystyle H_{x}=\int _{0}^{1}{\frac {1-t^{x}}{1-t}}\,dt=-\sum _{k=1}^{\infty }{x \choose k}{\frac {(-1)^{k}}{k}}}$$

 

are an integral and a series representation for a function that interpolates the harmonic numbers and, via analytic continuation, extends the definition to the complex plane other than the negative integers x. The interpolating function is in fact closely related to the digamma function

$${\displaystyle H_{x}=\psi (x+1)+\gamma ,}$$

 

where ψ(x) is the digamma function, and γ is the Euler–Mascheroni constant. The integration process may be repeated to obtain

$${\displaystyle H_{x,2}=-\sum _{k=1}^{\infty }{\frac {(-1)^{k}}{k}}{x \choose k}H_{k}.}$$

 

The Taylor series for the harmonic numbers is

$${\displaystyle H_{x}=\sum _{k=2}^{\infty }(-1)^{k}\zeta (k)\;x^{k-1}\quad {\text{ for }}|x|<1}$$

 

which comes from the Taylor series for the digamma function (${\displaystyle \zeta }$  is the Riemann zeta function).

Alternative, asymptotic formulation

When seeking to approximate H_x for a complex number x, it is effective to first compute H_m for some large integer m. Use that as an approximation for the value of H_m+x. Then use the recursion relation H_n = H_n−1 + 1/n backwards m times, to unwind it to an approximation for H_x. Furthermore, this approximation is exact in the limit as m goes to infinity.

Specifically, for a fixed integer n, it is the case that

$${\displaystyle \lim _{m\rightarrow \infty }\left[H_{m+n}-H_{m}\right]=0.}$$

 

If n is not an integer then it is not possible to say whether this equation is true because we have not yet (in this section) defined harmonic numbers for non-integers. However, we do get a unique extension of the harmonic numbers to the non-integers by insisting that this equation continue to hold when the arbitrary integer n is replaced by an arbitrary complex number x,

$${\displaystyle \lim _{m\rightarrow \infty }\left[H_{m+x}-H_{m}\right]=0\,.}$$

 

Swapping the order of the two sides of this equation and then subtracting them from H_x gives

$${\displaystyle {\begin{aligned}H_{x}&=\lim _{m\rightarrow \infty }\left[H_{m}-(H_{m+x}-H_{x})\right]\\[6pt]&=\lim _{m\rightarrow \infty }\left[\left(\sum _{k=1}^{m}{\frac {1}{k}}\right)-\left(\sum _{k=1}^{m}{\frac {1}{x+k}}\right)\right]\\[6pt]&=\lim _{m\rightarrow \infty }\sum _{k=1}^{m}\left({\frac {1}{k}}-{\frac {1}{x+k}}\right)=x\sum _{k=1}^{\infty }{\frac {1}{k(x+k)}}\,.\end{aligned}}}$$

 

This infinite series converges for all complex numbers x except the negative integers, which fail because trying to use the recursion relation H_n = H_n−1 + 1/n backwards through the value n = 0 involves a division by zero. By this construction, the function that defines the harmonic number for complex values is the unique function that simultaneously satisfies (1) H₀ = 0, (2) H_x = H_x−1 + 1/x for all complex numbers x except the non-positive integers, and (3) lim_m→+∞ (H_m+x − H_m) = 0 for all complex values x.

This last formula can be used to show that

$${\displaystyle \int _{0}^{1}H_{x}\,dx=\gamma ,}$$

 

where γ is the Euler–Mascheroni constant or, more generally, for every n we have:

$${\displaystyle \int _{0}^{n}H_{x}\,dx=n\gamma +\ln(n!).}$$

 

Special values for fractional arguments

There are the following special analytic values for fractional arguments between 0 and 1, given by the integral

$${\displaystyle H_{\alpha }=\int _{0}^{1}{\frac {1-x^{\alpha }}{1-x}}\,dx\,.}$$

 

More values may be generated from the recurrence relation

$${\displaystyle H_{\alpha }=H_{\alpha -1}+{\frac {1}{\alpha }}\,,}$$

 

or from the reflection relation

$${\displaystyle H_{1-\alpha }-H_{\alpha }=\pi \cot {(\pi \alpha )}-{\frac {1}{\alpha }}+{\frac {1}{1-\alpha }}\,.}$$

 

For example:

$${\displaystyle H_{\frac {1}{2}}=2-2\ln {2}}$$

 

$${\displaystyle H_{\frac {1}{3}}=3-{\tfrac {\pi }{2{\sqrt {3}}}}-{\tfrac {3}{2}}\ln {3}}$$

 

$${\displaystyle H_{\frac {2}{3}}={\tfrac {3}{2}}(1-\ln {3})+{\sqrt {3}}{\tfrac {\pi }{6}}}$$

 

$${\displaystyle H_{\frac {1}{4}}=4-{\tfrac {\pi }{2}}-3\ln {2}}$$

 

$${\displaystyle H_{\frac {3}{4}}={\tfrac {4}{3}}-3\ln {2}+{\tfrac {\pi }{2}}}$$

 

$${\displaystyle H_{\frac {1}{6}}=6-{\tfrac {\pi }{2}}{\sqrt {3}}-2\ln {2}-{\tfrac {3}{2}}\ln {3}}$$

 

$${\displaystyle H_{\frac {1}{8}}=8-{\tfrac {\pi }{2}}-4\ln {2}-{\tfrac {1}{\sqrt {2}}}\left\{\pi +\ln \left(2+{\sqrt {2}}\right)-\ln \left(2-{\sqrt {2}}\right)\right\}}$$

 

$${\displaystyle H_{\frac {1}{12}}=12-3\left(\ln {2}+{\tfrac {\ln {3}}{2}}\right)-\pi \left(1+{\tfrac {\sqrt {3}}{2}}\right)+2{\sqrt {3}}\ln \left({\sqrt {2-{\sqrt {3}}}}\right)}$$

 

For positive integers p and q with p < q, we have:

$${\displaystyle H_{\frac {p}{q}}={\frac {q}{p}}+2\sum _{k=1}^{\lfloor {\frac {q-1}{2}}\rfloor }\cos \left({\frac {2\pi pk}{q}}\right)\ln \left({\sin \left({\frac {\pi k}{q}}\right)}\right)-{\frac {\pi }{2}}\cot \left({\frac {\pi p}{q}}\right)-\ln \left(2q\right)}$$

 

Relation to the Riemann zeta function

Some derivatives of fractional harmonic numbers are given by

$${\displaystyle {\begin{aligned}{\frac {d^{n}H_{x}}{dx^{n}}}&=(-1)^{n+1}n!\left[\zeta (n+1)-H_{x,n+1}\right]\\[6pt]{\frac {d^{n}H_{x,2}}{dx^{n}}}&=(-1)^{n+1}(n+1)!\left[\zeta (n+2)-H_{x,n+2}\right]\\[6pt]{\frac {d^{n}H_{x,3}}{dx^{n}}}&=(-1)^{n+1}{\frac {1}{2}}(n+2)!\left[\zeta (n+3)-H_{x,n+3}\right].\end{aligned}}}$$

 

And using Maclaurin series, we have for x < 1 that

$${\displaystyle {\begin{aligned}H_{x}&=\sum _{n=1}^{\infty }(-1)^{n+1}x^{n}\zeta (n+1)\\[5pt]H_{x,2}&=\sum _{n=1}^{\infty }(-1)^{n+1}(n+1)x^{n}\zeta (n+2)\\[5pt]H_{x,3}&={\frac {1}{2}}\sum _{n=1}^{\infty }(-1)^{n+1}(n+1)(n+2)x^{n}\zeta (n+3).\end{aligned}}}$$

 

For fractional arguments between 0 and 1 and for a > 1,

$${\displaystyle {\begin{aligned}H_{1/a}&={\frac {1}{a}}\left(\zeta (2)-{\frac {1}{a}}\zeta (3)+{\frac {1}{a^{2}}}\zeta (4)-{\frac {1}{a^{3}}}\zeta (5)+\cdots \right)\\[6pt]H_{1/a,\,2}&={\frac {1}{a}}\left(2\zeta (3)-{\frac {3}{a}}\zeta (4)+{\frac {4}{a^{2}}}\zeta (5)-{\frac {5}{a^{3}}}\zeta (6)+\cdots \right)\\[6pt]H_{1/a,\,3}&={\frac {1}{2a}}\left(2\cdot 3\zeta (4)-{\frac {3\cdot 4}{a}}\zeta (5)+{\frac {4\cdot 5}{a^{2}}}\zeta (6)-{\frac {5\cdot 6}{a^{3}}}\zeta (7)+\cdots \right).\end{aligned}}}$$

 

See also

• Watterson estimator
• Tajima's D
• Coupon collector's problem
• Jeep problem
• 100 prisoners problem
• Riemann zeta function
• List of sums of reciprocals
• False discovery rate#Benjamini–Yekutieli procedure
• Block-stacking problem

Notes

1. John H., Conway; Richard K., Guy (1995). The book of numbers. Copernicus.
2. Graham, Ronald L.; Knuth, Donald E.; Patashnik, Oren (1994). Concrete Mathematics. Addison-Wesley.
3. Sondow, Jonathan and Weisstein, Eric W. "Harmonic Number." From MathWorld--A Wolfram Web Resource. http://mathworld.wolfram.com/HarmonicNumber.html
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References

• Arthur T. Benjamin; Gregory O. Preston; Jennifer J. Quinn (2002). (PDF). Mathematics Magazine. 75 (2): 95–103. CiteSeerX 10.1.1.383.722. doi:10.2307/3219141. JSTOR 3219141. Archived from the original (PDF) on 2009-06-17. Retrieved 2005-08-08.
• Donald Knuth (1997). "Section 1.2.7: Harmonic Numbers". The Art of Computer Programming. Vol. 1: Fundamental Algorithms (Third ed.). Addison-Wesley. pp. 75–79. ISBN 978-0-201-89683-1.
• Ed Sandifer, How Euler Did It — Estimating the Basel problem 2005-05-13 at the Wayback Machine (2003)
• Paule, Peter; Schneider, Carsten (2003). "Computer Proofs of a New Family of Harmonic Number Identities" (PDF). Adv. Appl. Math. 31 (2): 359–378. doi:10.1016/s0196-8858(03)00016-2.
• Wenchang Chu (2004). "A Binomial Coefficient Identity Associated with Beukers' Conjecture on Apery Numbers" (PDF). The Electronic Journal of Combinatorics. 11: N15. doi:10.37236/1856.
• Ayhan Dil; István Mező (2008). "A Symmetric Algorithm for Hyperharmonic and Fibonacci Numbers". Applied Mathematics and Computation. 206 (2): 942–951. arXiv:0803.4388. doi:10.1016/j.amc.2008.10.013. S2CID 12130670.

External links

• Weisstein, Eric W. "Harmonic Number". MathWorld.

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