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Operator norm

In mathematics, the operator norm measures the "size" of certain linear operators by assigning each a real number called its operator norm. Formally, it is a norm defined on the space of bounded linear operators between two given normed vector spaces. Informally, the operator norm of a linear map is the maximum factor by which it "lengthens" vectors.

Introduction and definition edit

Given two normed vector spaces   and   (over the same base field, either the real numbers   or the complex numbers  ), a linear map   is continuous if and only if there exists a real number   such that[1]

 

The norm on the left is the one in   and the norm on the right is the one in  . Intuitively, the continuous operator   never increases the length of any vector by more than a factor of   Thus the image of a bounded set under a continuous operator is also bounded. Because of this property, the continuous linear operators are also known as bounded operators. In order to "measure the size" of   one can take the infimum of the numbers   such that the above inequality holds for all   This number represents the maximum scalar factor by which   "lengthens" vectors. In other words, the "size" of   is measured by how much it "lengthens" vectors in the "biggest" case. So we define the operator norm of   as

 

The infimum is attained as the set of all such   is closed, nonempty, and bounded from below.[2]

It is important to bear in mind that this operator norm depends on the choice of norms for the normed vector spaces   and  .

Examples edit

Every real  -by-  matrix corresponds to a linear map from   to   Each pair of the plethora of (vector) norms applicable to real vector spaces induces an operator norm for all  -by-  matrices of real numbers; these induced norms form a subset of matrix norms.

If we specifically choose the Euclidean norm on both   and   then the matrix norm given to a matrix   is the square root of the largest eigenvalue of the matrix   (where   denotes the conjugate transpose of  ).[3] This is equivalent to assigning the largest singular value of  

Passing to a typical infinite-dimensional example, consider the sequence space   which is an Lp space, defined by

 

This can be viewed as an infinite-dimensional analogue of the Euclidean space   Now consider a bounded sequence   The sequence   is an element of the space   with a norm given by

 

Define an operator   by pointwise multiplication:

 

The operator   is bounded with operator norm

 

This discussion extends directly to the case where   is replaced by a general   space with   and   replaced by  

Equivalent definitions edit

Let   be a linear operator between normed spaces. The first four definitions are always equivalent, and if in addition   then they are all equivalent:

 

If   then the sets in the last two rows will be empty, and consequently their supremums over the set   will equal   instead of the correct value of   If the supremum is taken over the set   instead, then the supremum of the empty set is   and the formulas hold for any  

Importantly, a linear operator   is not, in general, guaranteed to achieve its norm   on the closed unit ball   meaning that there might not exist any vector   of norm   such that   (if such a vector does exist and if   then   would necessarily have unit norm  ). R.C. James proved James's theorem in 1964, which states that a Banach space   is reflexive if and only if every bounded linear functional   achieves its norm on the closed unit ball.[4] It follows, in particular, that every non-reflexive Banach space has some bounded linear functional (a type of bounded linear operator) that does not achieve its norm on the closed unit ball.

If   is bounded then[5]

 
and[5]
 
where   is the transpose of   which is the linear operator defined by  

Properties edit

The operator norm is indeed a norm on the space of all bounded operators between   and  . This means

 
 
 

The following inequality is an immediate consequence of the definition:

 

The operator norm is also compatible with the composition, or multiplication, of operators: if  ,   and   are three normed spaces over the same base field, and   and   are two bounded operators, then it is a sub-multiplicative norm, that is:

 

For bounded operators on  , this implies that operator multiplication is jointly continuous.

It follows from the definition that if a sequence of operators converges in operator norm, it converges uniformly on bounded sets.

Table of common operator norms edit

By choosing different norms for the codomain, used in computing  , and the domain, used in computing  , we obtain different values for the operator norm. Some common operator norms are easy to calculate, and others are NP-hard. Except for the NP-hard norms, all these norms can be calculated in   operations (for an   matrix), with the exception of the   norm (which requires   operations for the exact answer, or fewer if you approximate it with the power method or Lanczos iterations).

Computability of Operator Norms[6]
Co-domain
     
Domain   Maximum   norm of a column Maximum   norm of a column Maximum   norm of a column
  NP-hard Maximum singular value Maximum   norm of a row
  NP-hard NP-hard Maximum   norm of a row

The norm of the adjoint or transpose can be computed as follows. We have that for any   then   where   are Hölder conjugate to   that is,   and  

Operators on a Hilbert space edit

Suppose   is a real or complex Hilbert space. If   is a bounded linear operator, then we have

 
and
 
where   denotes the adjoint operator of   (which in Euclidean spaces with the standard inner product corresponds to the conjugate transpose of the matrix  ).

In general, the spectral radius of   is bounded above by the operator norm of  :

 

To see why equality may not always hold, consider the Jordan canonical form of a matrix in the finite-dimensional case. Because there are non-zero entries on the superdiagonal, equality may be violated. The quasinilpotent operators is one class of such examples. A nonzero quasinilpotent operator   has spectrum   So   while  

However, when a matrix   is normal, its Jordan canonical form is diagonal (up to unitary equivalence); this is the spectral theorem. In that case it is easy to see that

 

This formula can sometimes be used to compute the operator norm of a given bounded operator  : define the Hermitian operator   determine its spectral radius, and take the square root to obtain the operator norm of  

The space of bounded operators on   with the topology induced by operator norm, is not separable. For example, consider the Lp space   which is a Hilbert space. For   let   be the characteristic function of   and   be the multiplication operator given by   that is,

 

Then each   is a bounded operator with operator norm 1 and

 

But   is an uncountable set. This implies the space of bounded operators on   is not separable, in operator norm. One can compare this with the fact that the sequence space   is not separable.

The associative algebra of all bounded operators on a Hilbert space, together with the operator norm and the adjoint operation, yields a C*-algebra.

See also edit

Notes edit

  1. ^ Kreyszig, Erwin (1978), Introductory functional analysis with applications, John Wiley & Sons, p. 97, ISBN 9971-51-381-1
  2. ^ See e.g. Lemma 6.2 of Aliprantis & Border (2007).
  3. ^ Weisstein, Eric W. "Operator Norm". mathworld.wolfram.com. Retrieved 2020-03-14.
  4. ^ Diestel 1984, p. 6.
  5. ^ a b Rudin 1991, pp. 92–115.
  6. ^ section 4.3.1, Joel Tropp's PhD thesis, [1]

References edit

operator, norm, mathematics, operator, norm, measures, size, certain, linear, operators, assigning, each, real, number, called, operator, norm, formally, norm, defined, space, bounded, linear, operators, between, given, normed, vector, spaces, informally, oper. In mathematics the operator norm measures the size of certain linear operators by assigning each a real number called its operator norm Formally it is a norm defined on the space of bounded linear operators between two given normed vector spaces Informally the operator norm T displaystyle T of a linear map T X Y displaystyle T X to Y is the maximum factor by which it lengthens vectors Contents 1 Introduction and definition 2 Examples 3 Equivalent definitions 4 Properties 5 Table of common operator norms 6 Operators on a Hilbert space 7 See also 8 Notes 9 ReferencesIntroduction and definition editGiven two normed vector spaces V displaystyle V nbsp and W displaystyle W nbsp over the same base field either the real numbers R displaystyle mathbb R nbsp or the complex numbers C displaystyle mathbb C nbsp a linear map A V W displaystyle A V to W nbsp is continuous if and only if there exists a real number c displaystyle c nbsp such that 1 A v c v for all v V displaystyle Av leq c v quad mbox for all v in V nbsp The norm on the left is the one in W displaystyle W nbsp and the norm on the right is the one in V displaystyle V nbsp Intuitively the continuous operator A displaystyle A nbsp never increases the length of any vector by more than a factor of c displaystyle c nbsp Thus the image of a bounded set under a continuous operator is also bounded Because of this property the continuous linear operators are also known as bounded operators In order to measure the size of A displaystyle A nbsp one can take the infimum of the numbers c displaystyle c nbsp such that the above inequality holds for all v V displaystyle v in V nbsp This number represents the maximum scalar factor by which A displaystyle A nbsp lengthens vectors In other words the size of A displaystyle A nbsp is measured by how much it lengthens vectors in the biggest case So we define the operator norm of A displaystyle A nbsp as A o p inf c 0 A v c v for all v V displaystyle A op inf c geq 0 Av leq c v mbox for all v in V nbsp The infimum is attained as the set of all such c displaystyle c nbsp is closed nonempty and bounded from below 2 It is important to bear in mind that this operator norm depends on the choice of norms for the normed vector spaces V displaystyle V nbsp and W displaystyle W nbsp Examples editEvery real m displaystyle m nbsp by n displaystyle n nbsp matrix corresponds to a linear map from R n displaystyle mathbb R n nbsp to R m displaystyle mathbb R m nbsp Each pair of the plethora of vector norms applicable to real vector spaces induces an operator norm for all m displaystyle m nbsp by n displaystyle n nbsp matrices of real numbers these induced norms form a subset of matrix norms If we specifically choose the Euclidean norm on both R n displaystyle mathbb R n nbsp and R m displaystyle mathbb R m nbsp then the matrix norm given to a matrix A displaystyle A nbsp is the square root of the largest eigenvalue of the matrix A A displaystyle A A nbsp where A displaystyle A nbsp denotes the conjugate transpose of A displaystyle A nbsp 3 This is equivalent to assigning the largest singular value of A displaystyle A nbsp Passing to a typical infinite dimensional example consider the sequence space ℓ 2 displaystyle ell 2 nbsp which is an Lp space defined byl 2 a n n 1 a n C n a n 2 lt displaystyle l 2 left left a n right n geq 1 a n in mathbb C sum n a n 2 lt infty right nbsp This can be viewed as an infinite dimensional analogue of the Euclidean space C n displaystyle mathbb C n nbsp Now consider a bounded sequence s s n n 1 displaystyle s bullet left s n right n 1 infty nbsp The sequence s displaystyle s bullet nbsp is an element of the space ℓ displaystyle ell infty nbsp with a norm given by s sup n s n displaystyle left s bullet right infty sup n left s n right nbsp Define an operator T s displaystyle T s nbsp by pointwise multiplication a n n 1 T s s n a n n 1 displaystyle left a n right n 1 infty stackrel T s mapsto left s n cdot a n right n 1 infty nbsp The operator T s displaystyle T s nbsp is bounded with operator norm T s o p s displaystyle left T s right op left s bullet right infty nbsp This discussion extends directly to the case where ℓ 2 displaystyle ell 2 nbsp is replaced by a general L p displaystyle L p nbsp space with p gt 1 displaystyle p gt 1 nbsp and ℓ displaystyle ell infty nbsp replaced by L displaystyle L infty nbsp Equivalent definitions editLet A V W displaystyle A V to W nbsp be a linear operator between normed spaces The first four definitions are always equivalent and if in addition V 0 displaystyle V neq 0 nbsp then they are all equivalent A o p inf c 0 A v c v for all v V sup A v v 1 and v V sup A v v lt 1 and v V sup A v v 0 1 and v V sup A v v 1 and v V this equality holds if and only if V 0 sup A v v v 0 and v V this equality holds if and only if V 0 displaystyle begin alignedat 4 A op amp inf amp amp c geq 0 amp amp Av leq c v amp amp mbox for all amp amp v in V amp sup amp amp Av amp amp v leq 1 amp amp mbox and amp amp v in V amp sup amp amp Av amp amp v lt 1 amp amp mbox and amp amp v in V amp sup amp amp Av amp amp v in 0 1 amp amp mbox and amp amp v in V amp sup amp amp Av amp amp v 1 amp amp mbox and amp amp v in V text this equality holds if and only if V neq 0 amp sup amp amp bigg frac Av v amp amp v neq 0 amp amp mbox and amp amp v in V bigg text this equality holds if and only if V neq 0 end alignedat nbsp If V 0 displaystyle V 0 nbsp then the sets in the last two rows will be empty and consequently their supremums over the set displaystyle infty infty nbsp will equal displaystyle infty nbsp instead of the correct value of 0 displaystyle 0 nbsp If the supremum is taken over the set 0 displaystyle 0 infty nbsp instead then the supremum of the empty set is 0 displaystyle 0 nbsp and the formulas hold for any V displaystyle V nbsp Importantly a linear operator A V W displaystyle A V to W nbsp is not in general guaranteed to achieve its norm A o p sup A v v 1 v V displaystyle A op sup Av v leq 1 v in V nbsp on the closed unit ball v V v 1 displaystyle v in V v leq 1 nbsp meaning that there might not exist any vector u V displaystyle u in V nbsp of norm u 1 displaystyle u leq 1 nbsp such that A o p A u displaystyle A op Au nbsp if such a vector does exist and if A 0 displaystyle A neq 0 nbsp then u displaystyle u nbsp would necessarily have unit norm u 1 displaystyle u 1 nbsp R C James proved James s theorem in 1964 which states that a Banach space V displaystyle V nbsp is reflexive if and only if every bounded linear functional f V displaystyle f in V nbsp achieves its norm on the closed unit ball 4 It follows in particular that every non reflexive Banach space has some bounded linear functional a type of bounded linear operator that does not achieve its norm on the closed unit ball If A V W displaystyle A V to W nbsp is bounded then 5 A o p sup w A v v 1 w 1 where v V w W displaystyle A op sup left left w Av right v leq 1 left w right leq 1 text where v in V w in W right nbsp and 5 A o p t A o p displaystyle A op left t A right op nbsp where t A W V displaystyle t A W to V nbsp is the transpose of A V W displaystyle A V to W nbsp which is the linear operator defined by w w A displaystyle w mapsto w circ A nbsp Properties editThe operator norm is indeed a norm on the space of all bounded operators between V displaystyle V nbsp and W displaystyle W nbsp This means A o p 0 and A o p 0 if and only if A 0 displaystyle A op geq 0 mbox and A op 0 mbox if and only if A 0 nbsp a A o p a A o p for every scalar a displaystyle aA op a A op mbox for every scalar a nbsp A B o p A o p B o p displaystyle A B op leq A op B op nbsp The following inequality is an immediate consequence of the definition A v A o p v for every v V displaystyle Av leq A op v mbox for every v in V nbsp The operator norm is also compatible with the composition or multiplication of operators if V displaystyle V nbsp W displaystyle W nbsp and X displaystyle X nbsp are three normed spaces over the same base field and A V W displaystyle A V to W nbsp and B W X displaystyle B W to X nbsp are two bounded operators then it is a sub multiplicative norm that is B A o p B o p A o p displaystyle BA op leq B op A op nbsp For bounded operators on V displaystyle V nbsp this implies that operator multiplication is jointly continuous It follows from the definition that if a sequence of operators converges in operator norm it converges uniformly on bounded sets Table of common operator norms editBy choosing different norms for the codomain used in computing A v displaystyle Av nbsp and the domain used in computing v displaystyle v nbsp we obtain different values for the operator norm Some common operator norms are easy to calculate and others are NP hard Except for the NP hard norms all these norms can be calculated in N 2 displaystyle N 2 nbsp operations for an N N displaystyle N times N nbsp matrix with the exception of the ℓ 2 ℓ 2 displaystyle ell 2 ell 2 nbsp norm which requires N 3 displaystyle N 3 nbsp operations for the exact answer or fewer if you approximate it with the power method or Lanczos iterations Computability of Operator Norms 6 Co domainℓ 1 displaystyle ell 1 nbsp ℓ 2 displaystyle ell 2 nbsp ℓ displaystyle ell infty nbsp Domain ℓ 1 displaystyle ell 1 nbsp Maximum ℓ 1 displaystyle ell 1 nbsp norm of a column Maximum ℓ 2 displaystyle ell 2 nbsp norm of a column Maximum ℓ displaystyle ell infty nbsp norm of a columnℓ 2 displaystyle ell 2 nbsp NP hard Maximum singular value Maximum ℓ 2 displaystyle ell 2 nbsp norm of a rowℓ displaystyle ell infty nbsp NP hard NP hard Maximum ℓ 1 displaystyle ell 1 nbsp norm of a rowThe norm of the adjoint or transpose can be computed as follows We have that for any p q displaystyle p q nbsp then A p q A q p displaystyle A p rightarrow q A q rightarrow p nbsp where p q displaystyle p q nbsp are Holder conjugate to p q displaystyle p q nbsp that is 1 p 1 p 1 displaystyle 1 p 1 p 1 nbsp and 1 q 1 q 1 displaystyle 1 q 1 q 1 nbsp Operators on a Hilbert space editSuppose H displaystyle H nbsp is a real or complex Hilbert space If A H H displaystyle A H to H nbsp is a bounded linear operator then we have A o p A o p displaystyle A op left A right op nbsp and A A o p A o p 2 displaystyle left A A right op A op 2 nbsp where A displaystyle A nbsp denotes the adjoint operator of A displaystyle A nbsp which in Euclidean spaces with the standard inner product corresponds to the conjugate transpose of the matrix A displaystyle A nbsp In general the spectral radius of A displaystyle A nbsp is bounded above by the operator norm of A displaystyle A nbsp r A A o p displaystyle rho A leq A op nbsp To see why equality may not always hold consider the Jordan canonical form of a matrix in the finite dimensional case Because there are non zero entries on the superdiagonal equality may be violated The quasinilpotent operators is one class of such examples A nonzero quasinilpotent operator A displaystyle A nbsp has spectrum 0 displaystyle 0 nbsp So r A 0 displaystyle rho A 0 nbsp while A o p gt 0 displaystyle A op gt 0 nbsp However when a matrix N displaystyle N nbsp is normal its Jordan canonical form is diagonal up to unitary equivalence this is the spectral theorem In that case it is easy to see thatr N N o p displaystyle rho N N op nbsp This formula can sometimes be used to compute the operator norm of a given bounded operator A displaystyle A nbsp define the Hermitian operator B A A displaystyle B A A nbsp determine its spectral radius and take the square root to obtain the operator norm of A displaystyle A nbsp The space of bounded operators on H displaystyle H nbsp with the topology induced by operator norm is not separable For example consider the Lp space L 2 0 1 displaystyle L 2 0 1 nbsp which is a Hilbert space For 0 lt t 1 displaystyle 0 lt t leq 1 nbsp let W t displaystyle Omega t nbsp be the characteristic function of 0 t displaystyle 0 t nbsp and P t displaystyle P t nbsp be the multiplication operator given by W t displaystyle Omega t nbsp that is P t f f W t displaystyle P t f f cdot Omega t nbsp Then each P t displaystyle P t nbsp is a bounded operator with operator norm 1 and P t P s o p 1 for all t s displaystyle left P t P s right op 1 quad mbox for all quad t neq s nbsp But P t 0 lt t 1 displaystyle P t 0 lt t leq 1 nbsp is an uncountable set This implies the space of bounded operators on L 2 0 1 displaystyle L 2 0 1 nbsp is not separable in operator norm One can compare this with the fact that the sequence space ℓ displaystyle ell infty nbsp is not separable The associative algebra of all bounded operators on a Hilbert space together with the operator norm and the adjoint operation yields a C algebra See also editBanach Mazur compactum Set of n dimensional subspaces of a normed space made into a compact metric space Continuous linear operator Contraction operator theory Bounded operators with sub unit norm Discontinuous linear map Dual norm Measurement on a normed vector space Matrix norm Norm on a vector space of matrices Norm mathematics Length in a vector space Normed space Vector space on which a distance is definedPages displaying short descriptions of redirect targets Operator algebra Branch of functional analysis Operator theory Mathematical field of study Topologies on the set of operators on a Hilbert space Unbounded operator Linear operator defined on a dense linear subspaceNotes edit Kreyszig Erwin 1978 Introductory functional analysis with applications John Wiley amp Sons p 97 ISBN 9971 51 381 1 See e g Lemma 6 2 of Aliprantis amp Border 2007 Weisstein Eric W Operator Norm mathworld wolfram com Retrieved 2020 03 14 Diestel 1984 p 6 a b Rudin 1991 pp 92 115 section 4 3 1 Joel Tropp s PhD thesis 1 References editAliprantis Charalambos D Border Kim C 2007 Infinite Dimensional Analysis A Hitchhiker s Guide Springer p 229 ISBN 9783540326960 Conway John B 1990 III 2 Linear Operators on Normed Spaces A Course in Functional Analysis New York Springer Verlag pp 67 69 ISBN 0 387 97245 5 Diestel Joe 1984 Sequences and series in Banach spaces New York Springer Verlag ISBN 0 387 90859 5 OCLC 9556781 Rudin Walter 1991 Functional Analysis International Series in Pure and Applied Mathematics Vol 8 Second ed New York NY McGraw Hill Science Engineering Math ISBN 978 0 07 054236 5 OCLC 21163277 Retrieved from https en wikipedia org w index php title Operator norm amp oldid 1177421502, wikipedia, wiki, book, books, library,

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