1892 United States presidential election in Delaware

Main article: 1892 United States presidential election

The 1892 United States presidential election in Delaware took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

1892 United States presidential election in Delaware

← 1888 November 8, 1892 1896 →

Nominee Grover Cleveland Benjamin Harrison Party Democratic Republican Home state New York Indiana Running mate Adlai Stevenson I Whitelaw Reid Electoral vote 3 0 Popular vote 18,581 18,077 Percentage 49.90% 48.55%

County Results Cleveland   40-50%   50-60%

President before election Benjamin Harrison Republican Elected President Grover Cleveland Democratic

Delaware was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois.

Despite reclaiming the presidency, Cleveland performed much worse in Delaware than he did in his 1888 re-election bid. The State shifted 10 points for Harrison, voting for Cleveland by only 1.4 percentage points. This would be one of four states where Harrison outperformed his initial run for the presidency in 1888, these other states were New Hampshire, Georgia and, South Carolina.

Results

1892 United States presidential election in Delaware^[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Grover Cleveland	18,581	49.90%	3
	Republican	Benjamin Harrison (incumbent)	18,077	48.55%	0
	Prohibition	John Bidwell	564	1.51%	0
	Write-ins	Scattered	13	0.03%	0
Totals			37,235	100.00%	3
Voter turnout					—

See also

• United States presidential elections in Delaware

References

1. Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware

Notes