1996 United States House of Representatives elections in Kansas

The 1996 United States House of Representatives elections in Kansas were held on November 5, 1996 to determine who will represent the state of Kansas in the United States House of Representatives. Kansas has four seats in the House, apportioned according to the 1990 United States census. Representatives are elected for two-year terms.

1996 United States House of Representatives elections in Kansas

← 1994 November 5, 1996 1998 →
All 4 Kansas seats to the United States House of Representatives
Majority party Minority party   Party Republican Democratic Last election 4 0 Seats won 4 0 Seat change Popular vote 591,146 424,984 Percentage 56.36% 40.52% Swing 7.15% 4.03%
Republican   40–50%   50–60%   70–80%

Overview

United States House of Representatives elections in Kansas, 1996^[1]
Party		Votes	Percentage	Seats	+/–
	Republican	591,146	56.36%	4	-
	Democratic	424,984	40.52%	0	-
	Libertarian	23,253	2.22%	0	-
	Reform	9,495	0.91%	0	-
Totals		1,048,878	100.00%	4	-

References

1. Clerk of the U.S. House of Representatives. "Statistics of the Presidential and Congressional Election of November 5, 1996" (PDF). U.S. Government Printing Office. p. 25.