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1828 United States presidential election in Indiana

The 1828 United States presidential election in Indiana took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

1828 United States presidential election in Indiana

← 1824 October 31 – December 2, 1828 1832 →
 
Nominee Andrew Jackson John Quincy Adams
Party Democratic National Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun Richard Rush
Electoral vote 5 0
Popular vote 22,257 17,052
Percentage 56.62% 43.38%

Indiana voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Indiana by a margin of 13.24%.

Results Edit

1828 United States presidential election in Indiana[1]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson 22,257 56.62% 5
National Republican John Quincy Adams (incumbent) 17,052 43.38% 0
Totals 39,309 100.0% 5

See also Edit

References Edit

  1. ^ "1828 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved 28 February 2013.

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