fbpx
Wikipedia

Tutte theorem

In the mathematical discipline of graph theory the Tutte theorem, named after William Thomas Tutte, is a characterization of finite undirected graphs with perfect matchings. It is a generalization of Hall's marriage theorem from bipartite to arbitrary graphs.[clarification needed] It is a special case of the Tutte–Berge formula.

Example of a graph and one of its perfect matchings (in red).

Intuition edit

 
An graph (or a component) with an odd number of vertices cannot have a perfect matching, since there will always be a vertex left alone.

The goal is to characterize all graphs that do not have a perfect matching. Start with the most obvious case of a graph without a perfect matching: a graph with an odd number of vertices. In such a graph, any matching leaves at least one unmatched vertex, so it cannot be perfect.

A slightly more general case is a disconnected graph in which one or more components have an odd number of vertices (even if the total number of vertices is even). Let us call such components odd components. In any matching, each vertex can only be matched to vertices in the same component. Therefore, any matching leaves at least one unmatched vertex in every odd component, so it cannot be perfect.

Next, consider a graph G with a vertex u such that, if we remove from G the vertex u and its adjacent edges, the remaining graph (denoted G − u) has two or more odd components. As above, any matching leaves, in every odd component, at least one vertex that is unmatched to other vertices in the same component. Such a vertex can only be matched to u. But since there are two or more unmatched vertices, and only one of them can be matched to u, at least one other vertex remains unmatched, so the matching is not perfect.

Finally, consider a graph G with a set of vertices U such that, if we remove from G the vertices in U and all edges adjacent to them, the remaining graph (denoted G − U) has more than |U| odd components. As explained above, any matching leaves at least one unmatched vertex in every odd component, and these can be matched only to vertices of U - but there are not enough vertices on U for all these unmatched vertices, so the matching is not perfect.

We have arrived at a necessary condition: if G has a perfect matching, then for every vertex subset U in G, the graph G − U has at most |U| odd components. Tutte's theorem says that this condition is both necessary and sufficient for the existence of perfect matching.

Tutte's theorem edit

A graph, G = (VE), has a perfect matching if and only if for every subset U of V, the subgraph G − U has at most |U| odd components (connected components having an odd number of vertices).[1]

Proof edit

First we write the condition:

 

where   denotes the number of odd components of the subgraph induced by  .

Necessity of (∗): This direction was already discussed in the section Intuition below, but let us sum up here the proof. Consider a graph G, with a perfect matching. Let U be an arbitrary subset of V. Delete U. Let C be an arbitrary odd component in G − U. Since G had a perfect matching, at least one vertex in C must be matched to a vertex in U. Hence, each odd component has at least one vertex matched with a vertex in U. Since each vertex in U can be in this relation with at most one connected component (because of it being matched at most once in a perfect matching), odd(G − U) ≤ |U|.[2]

Sufficiency of (∗): Let G be an arbitrary graph with no perfect matching. We will find a so-called Tutte violator, that is, a subset S of V such that |S| < odd(G − S). We can suppose that G is edge-maximal, i.e., G + e has a perfect matching for every edge e not present in G already. Indeed, if we find a Tutte violator S in edge-maximal graph G, then S is also a Tutte violator in every spanning subgraph of G, as every odd component of G − S will be split into possibly more components at least one of which will again be odd.

We define S to be the set of vertices with degree |V| − 1. First we consider the case where all components of G − S are complete graphs. Then S has to be a Tutte violator, since if odd(G − S) ≤ |S|, then we could find a perfect matching by matching one vertex from every odd component with a vertex from S and pairing up all other vertices (this will work unless |V| is odd, but then is a Tutte violator).

Now suppose that K is a component of G − S and xy ∈ K are vertices such that xy ∉ E. Let xab ∈ K be the first vertices on a shortest x,y-path in K. This ensures that xaab ∈ E and xb ∉ E. Since a ∉ S, there exists a vertex c such that ac ∉ E. From the edge-maximality of G, we define M1 as a perfect matching in G + xb and M2 as a perfect matching in G + ac. Observe that surely xb ∈ M1 and ac ∈ M2.

Let P be the maximal path in G that starts from c with an edge from M1 and whose edges alternate between M1 and M2. How can P end? Unless we arrive at 'special' vertex such as xa or b, we can always continue: c is M2-matched by ca, so the first edge of P is not in M2, therefore the second vertex is M2-matched by a different edge and we continue in this manner.

Let v denote the last vertex of P. If the last edge of P is in M1, then v has to be a, since otherwise we could continue with an edge from M2 (even to arrive at x or b). In this case we define C:=P + ac. If the last edge of P is in M2, then surely v ∈ {xb} for analogous reason and we define C:=P + va + ac.

Now C is a cycle in G + ac of even length with every other edge in M2. We can now define M:=M2 Δ C (where Δ is symmetric difference) and we obtain a perfect matching in G, a contradiction.

Equivalence to the Tutte-Berge formula edit

The Tutte–Berge formula says that the size of a maximum matching of a graph   equals  . Equivalently, the number of unmatched vertices in a maximum matching equals  .

This formula follows from Tutte's theorem, together with the observation that   has a matching of size   if and only if the graph   obtained by adding   new vertices, each joined to every original vertex of  , has a perfect matching. Since any set   which separates   into more than   components must contain all the new vertices, (*) is satisfied for   if and only if  .

In infinite graphs edit

For connected infinite graphs that are locally finite (every vertex has finite degree), a generalization of Tutte's condition holds: such graphs have perfect matchings if and only if there is no finite subset, the removal of which creates a number of finite odd components larger than the size of the subset.[3]

See also edit

Notes edit

  1. ^ Lovász & Plummer (1986), p.  84; Bondy & Murty (1976), Theorem 5.4, p. 76.
  2. ^ Bondy & Murty (1976), pp. 76–78.
  3. ^ Tutte, W. T. (1950). "The factorization of locally finite graphs". Canadian Journal of Mathematics. 2: 44–49. doi:10.4153/cjm-1950-005-2. MR 0032986. S2CID 124434131.

References edit

tutte, theorem, confused, with, tutte, homotopy, theorem, tutte, spring, theorem, mathematical, discipline, graph, theory, named, after, william, thomas, tutte, characterization, finite, undirected, graphs, with, perfect, matchings, generalization, hall, marri. Not to be confused with Tutte homotopy theorem or Tutte s spring theorem In the mathematical discipline of graph theory the Tutte theorem named after William Thomas Tutte is a characterization of finite undirected graphs with perfect matchings It is a generalization of Hall s marriage theorem from bipartite to arbitrary graphs clarification needed It is a special case of the Tutte Berge formula Example of a graph and one of its perfect matchings in red Contents 1 Intuition 2 Tutte s theorem 3 Proof 4 Equivalence to the Tutte Berge formula 5 In infinite graphs 6 See also 7 Notes 8 ReferencesIntuition edit nbsp An graph or a component with an odd number of vertices cannot have a perfect matching since there will always be a vertex left alone The goal is to characterize all graphs that do not have a perfect matching Start with the most obvious case of a graph without a perfect matching a graph with an odd number of vertices In such a graph any matching leaves at least one unmatched vertex so it cannot be perfect A slightly more general case is a disconnected graph in which one or more components have an odd number of vertices even if the total number of vertices is even Let us call such components odd components In any matching each vertex can only be matched to vertices in the same component Therefore any matching leaves at least one unmatched vertex in every odd component so it cannot be perfect Next consider a graph G with a vertex u such that if we remove from G the vertex u and its adjacent edges the remaining graph denoted G u has two or more odd components As above any matching leaves in every odd component at least one vertex that is unmatched to other vertices in the same component Such a vertex can only be matched to u But since there are two or more unmatched vertices and only one of them can be matched to u at least one other vertex remains unmatched so the matching is not perfect Finally consider a graph G with a set of vertices U such that if we remove from G the vertices in U and all edges adjacent to them the remaining graph denoted G U has more than U odd components As explained above any matching leaves at least one unmatched vertex in every odd component and these can be matched only to vertices of U but there are not enough vertices on U for all these unmatched vertices so the matching is not perfect We have arrived at a necessary condition if G has a perfect matching then for every vertex subset U in G the graph G U has at most U odd components Tutte s theorem says that this condition is both necessary and sufficient for the existence of perfect matching Tutte s theorem editA graph G V E has a perfect matching if and only if for every subset U of V the subgraph G U has at most U odd components connected components having an odd number of vertices 1 Proof editFirst we write the condition U V o d d G U U displaystyle qquad forall U subseteq V quad odd G U leq U nbsp where o d d X displaystyle odd X nbsp denotes the number of odd components of the subgraph induced by X displaystyle X nbsp Necessity of This direction was already discussed in the section Intuition below but let us sum up here the proof Consider a graph G with a perfect matching Let U be an arbitrary subset of V Delete U Let C be an arbitrary odd component in G U Since G had a perfect matching at least one vertex in C must be matched to a vertex in U Hence each odd component has at least one vertex matched with a vertex in U Since each vertex in U can be in this relation with at most one connected component because of it being matched at most once in a perfect matching odd G U U 2 Sufficiency of Let G be an arbitrary graph with no perfect matching We will find a so called Tutte violator that is a subset S of V such that S lt odd G S We can suppose that G is edge maximal i e G e has a perfect matching for every edge e not present in G already Indeed if we find a Tutte violator S in edge maximal graph G then S is also a Tutte violator in every spanning subgraph of G as every odd component of G S will be split into possibly more components at least one of which will again be odd We define S to be the set of vertices with degree V 1 First we consider the case where all components of G S are complete graphs Then S has to be a Tutte violator since if odd G S S then we could find a perfect matching by matching one vertex from every odd component with a vertex from S and pairing up all other vertices this will work unless V is odd but then is a Tutte violator Now suppose that K is a component of G S and x y K are vertices such that xy E Let x a b K be the first vertices on a shortest x y path in K This ensures that xa ab E and xb E Since a S there exists a vertex c such that ac E From the edge maximality of G we define M1 as a perfect matching in G xb and M2 as a perfect matching in G ac Observe that surely xb M1 and ac M2 Let P be the maximal path in G that starts from c with an edge from M1 and whose edges alternate between M1 and M2 How can P end Unless we arrive at special vertex such as x a or b we can always continue c is M2 matched by ca so the first edge of P is not in M2 therefore the second vertex is M2 matched by a different edge and we continue in this manner Let v denote the last vertex of P If the last edge of P is in M1 then v has to be a since otherwise we could continue with an edge from M2 even to arrive at x or b In this case we define C P ac If the last edge of P is in M2 then surely v x b for analogous reason and we define C P va ac Now C is a cycle in G ac of even length with every other edge in M2 We can now define M M2 D C where D is symmetric difference and we obtain a perfect matching in G a contradiction Equivalence to the Tutte Berge formula editThe Tutte Berge formula says that the size of a maximum matching of a graph G V E displaystyle G V E nbsp equals min U V U odd G U V 2 displaystyle min U subseteq V left U operatorname odd G U V right 2 nbsp Equivalently the number of unmatched vertices in a maximum matching equals max U V odd G U U displaystyle max U subseteq V left operatorname odd G U U right nbsp This formula follows from Tutte s theorem together with the observation that G displaystyle G nbsp has a matching of size k displaystyle k nbsp if and only if the graph G k displaystyle G k nbsp obtained by adding V 2 k displaystyle V 2k nbsp new vertices each joined to every original vertex of G displaystyle G nbsp has a perfect matching Since any set X displaystyle X nbsp which separates G k displaystyle G k nbsp into more than X displaystyle X nbsp components must contain all the new vertices is satisfied for G k displaystyle G k nbsp if and only if k min U V U odd G U V 2 displaystyle k leq min U subseteq V left U operatorname odd G U V right 2 nbsp In infinite graphs editFor connected infinite graphs that are locally finite every vertex has finite degree a generalization of Tutte s condition holds such graphs have perfect matchings if and only if there is no finite subset the removal of which creates a number of finite odd components larger than the size of the subset 3 See also editBipartite matching Hall s marriage theorem Petersen s theoremNotes edit Lovasz amp Plummer 1986 p 84 Bondy amp Murty 1976 Theorem 5 4 p 76 Bondy amp Murty 1976 pp 76 78 Tutte W T 1950 The factorization of locally finite graphs Canadian Journal of Mathematics 2 44 49 doi 10 4153 cjm 1950 005 2 MR 0032986 S2CID 124434131 References editBondy J A Murty U S R 1976 Graph theory with applications New York American Elsevier Pub Co ISBN 0 444 19451 7 Lovasz Laszlo Plummer M D 1986 Matching theory Amsterdam North Holland ISBN 0 444 87916 1 Retrieved from https en wikipedia org w index php title Tutte theorem amp oldid 1181953441, wikipedia, wiki, book, books, library,

article

, read, download, free, free download, mp3, video, mp4, 3gp, jpg, jpeg, gif, png, picture, music, song, movie, book, game, games.