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495 (number)

495 (four hundred [and] ninety-five) is the natural number following 494 and preceding 496. It is a pentatope number[1] (and so a binomial coefficient ). The maximal number of pieces that can be obtained by cutting an annulus with 30 cuts.[2]

Cardinalfour hundred ninety-five
Ordinal495th
(four hundred ninety-fifth)
Factorization32 × 5 × 11
Greek numeralΥϞΕ´
Roman numeralCDXCV
Binary1111011112
Ternary2001003
Senary21436
Octal7578
Duodecimal35312
Hexadecimal1EF16

Kaprekar transformation edit

The Kaprekar's routine algorithm is defined as follows for three-digit numbers:

  1. Take any three-digit number, other than repdigits such as 111. Leading zeros are allowed.
  2. Arrange the digits in descending and then in ascending order to get two three-digit numbers, adding leading zeros if necessary.
  3. Subtract the smaller number from the bigger number.
  4. Go back to step 2 and repeat.

Repeating this process will always reach 495 in a few steps. Once 495 is reached, the process stops because 954 – 459 = 495.

Example edit

For example, choose 495:

495

The only three-digit numbers for which this function does not work are repdigits such as 111, which give the answer 0 after a single iteration. All other three-digit numbers work if leading zeros are used to keep the number of digits at 3:

211 – 112 = 099
990 – 099 = 891 (rather than 99 – 99 = 0)
981 – 189 = 792
972 – 279 = 693
963 – 369 = 594
954 − 459 = 495

The number 6174 has the same property for the four-digit numbers, albeit has a much greater percentage of workable numbers. Sometimes these numbers (495, 6174, and their counterparts in other digit lengths or in bases other than 10) are called "Peyush constants" named after Peyush Dixit who solved this routine as a part of his IMO 2000 (International Mathematical Olympiad, Year 2000) thesis. [3]

See also edit

  • Collatz conjecture — sequence of unarranged-digit numbers always ends with the number 1.

References edit

  1. ^ "Sloane's A000332". The On-Line Encyclopedia of Integer Sequences. OEIS Foundation. Retrieved 2016-05-16.
  2. ^ Sloane, N. J. A. (ed.). "Sequence A000096". The On-Line Encyclopedia of Integer Sequences. OEIS Foundation.
  3. ^ Hanover 2017, p. 14, Operations.
  • Eldridge, Klaus E.; Sagong, Seok (February 1988). "The Determination of Kaprekar Convergence and Loop Convergence of All Three-Digit Numbers". The American Mathematical Monthly. 95 (2). The American Mathematical Monthly, Vol. 95, No. 2: 105–112. doi:10.2307/2323062. JSTOR 2323062.

number, four, hundred, ninety, five, natural, number, following, preceding, pentatope, number, binomial, coefficient, displaystyle, tbinom, maximal, number, pieces, that, obtained, cutting, annulus, with, cuts, list, numbersintegers, cardinalfour, hundred, nin. 495 four hundred and ninety five is the natural number following 494 and preceding 496 It is a pentatope number 1 and so a binomial coefficient 12 4 displaystyle tbinom 12 4 The maximal number of pieces that can be obtained by cutting an annulus with 30 cuts 2 494 495 496 List of numbersIntegers 0 100 200 300 400 500 600 700 800 900 Cardinalfour hundred ninety fiveOrdinal495th four hundred ninety fifth Factorization32 5 11Greek numeralYϞE Roman numeralCDXCVBinary1111011112Ternary2001003Senary21436Octal7578Duodecimal35312Hexadecimal1EF16 Contents 1 Kaprekar transformation 1 1 Example 2 See also 3 ReferencesKaprekar transformation editThe Kaprekar s routine algorithm is defined as follows for three digit numbers Take any three digit number other than repdigits such as 111 Leading zeros are allowed Arrange the digits in descending and then in ascending order to get two three digit numbers adding leading zeros if necessary Subtract the smaller number from the bigger number Go back to step 2 and repeat Repeating this process will always reach 495 in a few steps Once 495 is reached the process stops because 954 459 495 Example edit For example choose 495 495 The only three digit numbers for which this function does not work are repdigits such as 111 which give the answer 0 after a single iteration All other three digit numbers work if leading zeros are used to keep the number of digits at 3 211 112 099 990 099 891 rather than 99 99 0 981 189 792 972 279 693 963 369 594 954 459 495 The number 6174 has the same property for the four digit numbers albeit has a much greater percentage of workable numbers Sometimes these numbers 495 6174 and their counterparts in other digit lengths or in bases other than 10 are called Peyush constants named after Peyush Dixit who solved this routine as a part of his IMO 2000 International Mathematical Olympiad Year 2000 thesis 3 See also editCollatz conjecture sequence of unarranged digit numbers always ends with the number 1 References edit Sloane s A000332 The On Line Encyclopedia of Integer Sequences OEIS Foundation Retrieved 2016 05 16 Sloane N J A ed Sequence A000096 The On Line Encyclopedia of Integer Sequences OEIS Foundation Hanover 2017 p 14 Operations Eldridge Klaus E Sagong Seok February 1988 The Determination of Kaprekar Convergence and Loop Convergence of All Three Digit Numbers The American Mathematical Monthly 95 2 The American Mathematical Monthly Vol 95 No 2 105 112 doi 10 2307 2323062 JSTOR 2323062 Retrieved from https en wikipedia org w index php title 495 number amp oldid 1213797542, wikipedia, wiki, book, books, library,

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