1816 United States presidential election in Delaware

Main article: 1816 United States presidential election

The 1816 United States presidential election in Delaware took place between 1 November and 4 December 1816, as part of the 1816 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

1816 United States presidential election in Delaware

← 1812 1 November – 4 December 1816 1820 →

Nominee Rufus King James Monroe Party Federalist Democratic-Republican Home state New York Virginia Running mate John E. Howard Daniel D. Tompkins Electoral vote 3 0

Delaware cast three electoral votes for the Federalist candidate Rufus King over the Democratic-Republican candidate James Monroe. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote. However one of the four electors did not end up casting their vote. The three electoral votes for Vice president were also not cast for King's running mate John E. Howard, but for Federalist Robert Goodloe Harper from Maryland.^[1]

Results

1816 United States presidential election in Delaware^[2]
Party		Candidate	Votes	Percentage	Electoral votes
	Federalist	Rufus King	–	–	3
	Democratic-Republican	James Monroe	–	–	0
	None	Not Cast	–	–	1
Totals			–	–	4

See also

• United States presidential elections in Delaware

References

1. "1816 Presidential General Election Results". U.S. Election Atlas. Retrieved July 8, 2023.
2. "1816 Presidential Election". 270towin.com. Retrieved July 8, 2023.